We have a condition here, IF one die shows a 6, THEN what are the odds the other die shows a 6. The answer is 1/6. Each valid trial requires that one of the die shows a 6, or else it's not valid, rolling hard 10 or snakeeyes is dismissed.
Now, if the question is what are the odds of rolling a pair of 6's, then that's 1/36 ... we have 36 valid trials of which only one result makes a positive.
ETA: nin'ja'ed by the great LSLGuy
Last edited by watchwolf49; 10062016 at 11:17 AM.
