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Old 10-06-2016, 10:15 AM
watchwolf49 watchwolf49 is offline
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Join Date: Dec 2009
Location: State of Jefferson
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We have a condition here, IF one die shows a 6, THEN what are the odds the other die shows a 6. The answer is 1/6. Each valid trial requires that one of the die shows a 6, or else it's not valid, rolling hard 10 or snake-eyes is dismissed.

Now, if the question is what are the odds of rolling a pair of 6's, then that's 1/36 ... we have 36 valid trials of which only one result makes a positive.

ETA: nin'ja'ed by the great LSLGuy

Last edited by watchwolf49; 10-06-2016 at 10:17 AM.