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Old 10-06-2016, 10:38 AM
Ignotus Ignotus is offline
Join Date: Dec 2012
Posts: 978
Originally Posted by LSLGuy View Post
Late add:

You can restate the problem like this and it becomes really, really obvious:

A: Since the two dice don't communicate, the odds of the second one being a 6 are always 1/6. It doesn't matter what the other die is doing.

This is one of those puzzles where the trick is to ignore most of the setup since that's just there to distract you. "Now everybody watch my left hand very carefully as I fiddle with this magic wand..."
(My emphasis)

Ah, but they do in a way communicate, since you're told the pair contains "at least one 6". So, if neither die showed a 6, they wouldn't be on the table at all! So, if you are one of the dice, you can correctly infer: either myself, or that other die over there, is showing a 6!"