Quote:
Originally Posted by watchwolf49
I think we're confusing the odds of rolling at least one 6 with the OP. The OP gives us this one 6, we're asked the odds of the other being a 6. We only have six possible trial results; (6,1),(6,2),(6,3),(6,4),(6,5),(6,6); all other combinations are ignored.
The operative phrase in the OP is "'at least one of the dice is a 6.'", it doesn't matter which die is a 6.

But if we start not knowing if the red or green die, (for example,) is a 6, then we have 11 possible results at the early stage: (1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)