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Old 10-06-2016, 12:07 PM
x-ray vision x-ray vision is offline
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Join Date: Oct 2002
Location: N.J.
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Quote:
Originally Posted by Thudlow Boink View Post
As in the case of the infamous Monty Hall problem, one way of settling this would be experimentally.

Roll two fair dice. At least one of the dice should be a 6, so if this is not the case, re-roll until it is.

Now, remove a 6.

Does the remaining die show a 6? Write down YES or NO.

Repeat this experiment many times, and then calculate the number of YESes you wrote down, dividing by the total number of trials.
Right, but how is it that a 6 being removed is decided?

We have:

1,6
2,6
3,6
4,6
5,6
6,6
6,5
6,4
6,3
6,2
6,1

Is on pair of dice randomly chosen to have a 6 removed?: 1 out of 11 pairs.

Or is one die out of ever die showing a 6 in the running to be chose?: 1 out of 12 dice.

Last edited by x-ray vision; 10-06-2016 at 12:08 PM.