I'm blaming my confusion on LSLGuy.
Quote:
Originally Posted by LSLGuy
IMO the above part is right. Then you go wrong here:How many different ways can we remove a six? Let's assume we have a green and a red die so we can tell them apart. As you said, the possibilities expressed in green, red order are:
1,6
2,6
3,6
4,6
5,6
6,6
6,5
6,4
6,3
6,2
6,1
If the green die is a 6 we're looking at one of the bottom 6 possibilities. 1/6th of which have another 6, the red die.
If the red die is a 6 we're looking at one of the top 6 possibilities. 1/6th of which have another 6, the green die.
Result: it doesn't matter which die is a 6. Red, green, or both. After you remove one of the sixes the chance of the other being a 6 is 1/6.

He has every combination twice because order matters, but he doesn't for the 6,6 combination. The order of 6s matters too. So it should be:
1,6
2,6
3,6
4,6
5,6
6,6
6,6
6,5
6,4
6,3
6,2
6,1
Answer: 1 out of 6