I ran a simulation 100K times. I ignored any roll without at least one six. For the remaining rolls, here are the counts:

Code:

**Die occurrences %**
1 5428 17.7%
2 5627 18.4%
3 5533 18.1%
4 5536 18.1%
5 5690 18.6%
6 2801 9.1%

So assuming the interpretation that the question is asking about the odds over multiple rolls, the answer is clearly 1/11.

I understand

**markn+'s** point about the answer depending on how you interpret it, but the second interpretation of "on this

**one** roll where one die just happened to be 6, what are the odds the other one is a 6" doesn't work for me. The whole point of probabilities and odds is assuming what happens over multiple events. Pretending that we're talking only about this single roll isn't a probability. It smacks too much of "either it's a 6 or it's not, so the odds are 50/50."