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#1
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quark stars
Quark Stars were mentioned in this thread, and I'd like to hear some more information about them, but didn't want to completely hijack that thread.
Here's an article about their apparent discovery. My question is: where do these free quarks come from, and why do they remain free? I was under the impression that free quarks will hadronize almost instantaneously, and that it is impossible to remove quarks from hadrons because the binding force increases the further you pull them apart. I'm also puzzled by this quote from the article linked to above: Quote:
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#2
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What the color theorem says is that observed states are color singlets. Basically, each quark carries a three-dimensional "color vector" which transforms under the regular representation 3 of SU(3)color. A system of n quarks transforms as 3n: the nth tensor power of this representation (yes, tensor products and representation theory and group actions all wrapped up together. Seems someone was advocating this recently...). Observable states occupy the subspace of vectors in 3n left invariant by the action of the group. That is, decompose 3n as a direct sum of irreducible representations and pick out the 1-homogenous component. As a note: antiquarks add factors of the dual representation. Now, 3?3' = 1?8, so there's a one-dimensional space of observable color states of a quark and an antiquark: mesons. 3n = 1?8?8?10, and the 1 gives a space of color states for three quarks: baryons. Now, a year ago we already had discovered "pentaquarks", which in terms of color live in 34?3 = (1?8)?(1?8?8?10) Now I'm not going to distribute that tensor product over the direct sums on the right, but note that since each term has a 1 in it, there will be a direct summand of 1?1 = 1 in the result, leaving "room" for color-singlet pentaquark states. The puzzle was why none were ever seen. It was resolved when one was seen. Now, why couldn't a quark star occupy a singlet state in the decomposition of 3a rather awful lot? |
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#3
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Um, yeah. What Mathochist said.
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#4
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For those of us who were sick the day they taught Quantum Chromodynamics in Kindergarten is there a more layman's version? (I realize that dumbing it down for the unwashed masses loses perhaps important details but when those details are beyond us anyway I'm not sure it matters.) |
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#5
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The article quoted in the OP itself gives the version that's all that most of us, including me, will ever need:
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But they're no more free than the neutronium talked about in other recent threads would be free outside of this gravity squeezing. |
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#6
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#7
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Basically, they're not free quarks -- the star just becomes like one big hadron. That "cosmic wildfire" gibberish still strikes me as kind of odd, but I'm not losing any sleep over it. |
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#8
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Basically, you've got three states a quark can be in, commonly called "red, green, blue". There's a symmetry acting that exchanges these states among themselves. Something might swap red and green, another swaps red and blue, the composition shuffles them all around (red->green->blue->red). The only states that you're allowed to see in the real world are ones where the symmetry action does nothing. Let's label a quark state (fc), where f denotes a flavor (up or down, say) and c a color. The state (ur,ug,db), for instance, is one red up quark, one green up quark, and one blue down quark. If we swap green and blue, we get (ur,ub,dg), which is not the same state, so (ur,ug,db) isn't allowed. However, we can superpose states. Consider (ur,ug,db) + (ur,ub,dg) + (ug,ur,db) + (ug,ub,dr) + (ub,ur,dg) + (ub,ug,dr) Now any shuffling of the colors merely swaps around terms in the sum, and so gives back the same state. This is an allowed state, which we call the proton. Now a quark star can be composed of an awful lot of quarks with various flavor and color states such that the symmetry swapping around the colors leaves the total state invariant, but not one expressible as a simple collection of a bunch of nucleons (the distinction is subtle, but important). This would be seen as a blob composed of quarks as opposed to neutrons, but the state as a whole would not violate quark confinement. If you grok neutron stars, thinking about one as sort of a giant atomic nucleus, you're halfway there. A quark star isn't just a giant nucleus, but more like a giant nucleon: something like a neutron blown up to a macroscopic scale. I think the most interesting thing about this would be that (at least as it seems to me) it's essentially a quantum mechanical object at a macroscopic scale. In particular it has noticeable gravitational effects and may well be an useful object in studying the interaction between quantum mechanics and general relativity. |
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#9
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#10
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This particular subfield of physics isn't my specialty, but let me give it a shot:
There are two "stable" particles that are made out of quarks that exist on Earth: The neutron and the proton. Both are made out of quarks called "up" and "down" quarks; the neutron has one up quark and two down quarks, the proton two ups and one down. There are four other types of quarks, originally discovered in particle accelerators, called (in order of increasing mass) the "strange", "charm", "bottom", and "top." These heavier quarks will, in general, decay via the weak nuclear force into the lighter up and down quarks. Now, it was conjectured in the mid-80s (actually earlier, but the mid-80s was when people started paying attention to the possibility) that under sufficient temperature and pressure, you might be able to make a mix of up, down, and strange quarks stable. These wouldn't be grouped into particles as they are in neutrons, but instead you would have a "soup" of quarks running around whose color charges happened to cancel (this is essentially what Mathsochist was saying). It was further conjectured that the necessary conditions of temperature and pressure would be met in collapsing stars: a quark star would be even denser than a neutron star. Here's the fun part: it has also been conjectured that this "strange quark matter" is even more stable than "conventional quark matter" (i.e. neutrons and protons), even at low temperatures and pressures. Under this hypothesis, the only reason that we're still made of protons and neutrons is that there need to be a certain number of strange quarks around for SQM to be stable, and there just aren't that many on Earth. But if a sufficiently large chunk of SQM were to hit the Earth (for example), it would start a chain reaction that would convert the entire Earth into SQM. A close analog would be how water can be supercooled: liquid water can exist below 0 C, but if a "seed" is added for the ice crystals to start forming on, it'll immediately freeze. I think this is all correct, but like I said, this isn't my specialty. I welcome any corrections/additions/bitchslaps that someone more knowledgeable than me might give. Quote:
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#11
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#12
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) We can certainly make strange quarks.
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#13
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It may be that SQM will not eat the earth (or whatever it comes across) since there is speculation that some has hit the earth and we are all still here.
Did quark matter strike Earth? Admittedly more assumption than fact but interesting nonetheless. Is a Quark-Gluon Plasma (QGP) synonymous with Strange Quark Matter (SQM)? |
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#14
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__________________
Time travels in divers paces with divers persons. --As You Like It, III:ii:328 |
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#15
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#16
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First, a few observations:
1) Do not, under any circumstances, misread the word "hadron" as "hardon" in sentences such as tim314's ". . . the star just becomes like one big hadron." It only leads to confusion. 2) Since I'm sure someone else will point it out anyway, "Strange Quark Matter" would be a good name for a rock band. 3) There is no such place as Meson, Arizona. Now, regarding this contribution: Quote:
From the article: Quote:
RR |
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#17
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