The Straight Dope

Go Back   Straight Dope Message Board > Main > General Questions

Reply
 
Thread Tools Display Modes
  #1  
Old 03-20-2009, 01:46 PM
Frylock Frylock is offline
Guest
 
Join Date: Jun 2001
Physics Dopers: "Twinning" behavior?

On page 25 of this paper (It's Conway's first paper on his Free Will Theorem) he writes:

Quote:
Although we find ourselves unable to give an
operational definition of either “free” or “random,” we have managed to distinguish
between them in our context, because free behavior can be twinned,
while random behavior cannot (a remark that might also interest some philosphers
of free will).
I have tried to read through the section of the paper that explains what it means to "twin" behavior, but it's over my head.

Can anyone here explain it to a layman?
Reply With Quote
Advertisements  
  #2  
Old 03-20-2009, 02:14 PM
Half Man Half Wit Half Man Half Wit is offline
Guest
 
Join Date: Jun 2007
It basically refers to quantum entanglement -- Alice getting a spin up result in her measurement on one part of an entangled particle pair necessitates Bob's getting a spin down if he measures along the same axis, instantaneously, regardless of spatial separation. I'm not exactly sure how this applies to 'free behaviour', though, but I can see how it might be meant that it's impossible for 'random' behaviour to be twinned, since if one of the partners behaves randomly, the other can't, due to their entanglement -- the same way Alice's result is completely random, and Bob's then completely determined.
Reply With Quote
  #3  
Old 03-20-2009, 02:19 PM
ZenBeam ZenBeam is offline
Charter Member
 
Join Date: Oct 1999
Location: I'm right here!
Posts: 6,887
Quote:
Originally Posted by article
It is possible to produce two distantly separated spin 1 particles that are
“twinned,” meaning that they give the same answers to corresponding questions
2. A symmetrical form of the TWIN axiom would say that if the same
triple x, y, z were measured for each particle, possibly in different orders, then
the two particles’ responses to the experiments in individual directions would
be the same. For instance, if measurements in the order x, y, z for one particle
produced x → 1, y → 0, z → 1, then measurements in the order y, z, x for the
second particle would produce y → 0, z → 1, x → 1.‡ Although we could use

‡For simplicity, we have spoken of measuring x, y, z in that order, but nothing in the proof
is affected if they are measured simultaneously, as in the “spin-Hamiltonian” experiment of
Endnote 1.
This sounds like entangled particles(*), except that as I understand it, once one of the directions is measured, the entanglement breaks. So while the first particle measurement gives X → 1 (for both particles), the measurements for Y and Z are no longer entangled. In short, I guess, I question their assertion that twinned particles, as defined, exist.

* I've always heard that entangled particles have opposite spin, but that distinction probably isn't important here.
Reply With Quote
  #4  
Old 03-20-2009, 03:38 PM
Chronos Chronos is offline
Charter Member
 
Join Date: Jan 2000
Location: The Land of Cleves
Posts: 47,934
Quote:
* I've always heard that entangled particles have opposite spin, but that distinction probably isn't important here.
The easiest ways of producing entangled particles gets you opposite spins, but there probably is some way to get them with the same. You're right, though, that it isn't an important distinction.
Reply With Quote
  #5  
Old 03-20-2009, 07:18 PM
Omphaloskeptic Omphaloskeptic is offline
Guest
 
Join Date: Oct 2001
Quote:
Originally Posted by ZenBeam View Post
This sounds like entangled particles(*), except that as I understand it, once one of the directions is measured, the entanglement breaks. So while the first particle measurement gives X → 1 (for both particles), the measurements for Y and Z are no longer entangled. In short, I guess, I question their assertion that twinned particles, as defined, exist.

* I've always heard that entangled particles have opposite spin, but that distinction probably isn't important here.
It's a little more complicated than this. What you say is correct for the common example of a pair of spin-1/2 particles in the "spin-0 (singlet) state" |↑↓>-|↓↑> (*). A measurement of either particle's spin along the z axis will project the state into either |↑↓> or |↓↑>, so the two particles' spins must be oppositely directed. It turns out that the spin-0 state is rotationally invariant, so the same result actually holds for measurements along any axis.

However, the example given in the paper is for two spin-1 particles. These live in a three-dimensional Hilbert space, not a two-dimensional space like the spin-1/2 particles. This means that measuring the spin of one of these particles along the z axis has three possible results: |↑> (spin +1), |↓> (spin -1), and |0> (spin 0). The measurement proposed in the paper is chosen so that it does not distinguish between the states |↑> and |↓> (this is what it means when they say that it is measuring "the square of the component spin"); so a measurement result of 0 projects onto the state |0>, but a measurement result of 1 projects onto the subspace spanned by the states |↑> and |↓>. It turns out (as a simple consequence of the quantum-mechanics angular-momentum rules) that for a spin-1 particle, measuring the squares of the x, y, and z components of spins always produces two 1s and one 0. This is their "SPIN axiom" (discussed in their Endnote 1).

Because a single measurement does not fully project the particle state, it does not fully destroy the entanglement. This is what allows the three measurements to all give correlated results. As discussed in Endnote 2, the two-particle state is again the singlet state, a rotationally-invariant state of total spin 0. If the two experimenters actually measured the z-components of spin, they would get opposite results (|↑> and |↓> or |0> and |0>), but since they are only measuring the squared z-component, they always get the same answer.

(*) I'm ignoring normalization.
Reply With Quote
Reply

Bookmarks

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is Off
HTML code is Off
Forum Jump


All times are GMT -5. The time now is 01:32 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2013, Jelsoft Enterprises Ltd.

Send questions for Cecil Adams to: cecil@chicagoreader.com

Send comments about this website to: webmaster@straightdope.com

Terms of Use / Privacy Policy

Advertise on the Straight Dope!
(Your direct line to thousands of the smartest, hippest people on the planet, plus a few total dipsticks.)

Publishers - interested in subscribing to the Straight Dope?
Write to: sdsubscriptions@chicagoreader.com.

Copyright © 2013 Sun-Times Media, LLC.