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#1
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In the future won't it be possible to detect and measure gravity waves?
In theory couldn't you measure the speed and mass of a particle by the gravity waves it gives off moving though space? By measuring the gravity waves you could determine the particles direction and mass without interfering with it. Doesn't this make the Heisenberg's Uncertainty Principle and old theory? PerfectDark |
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#2
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The uncertainty principle states that the position and the velocity of an object cannot both be measured exactly, at the same time. The first question I'd raise is that your OP talks about recording direction and mass rather than position and velocity. Even using your hypothetical gravity meter, how are you going to record position and velocity at the same time?
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#3
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Quote:
In any case... Quote:
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#4
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Ooops.. sorry I was rushing the post because I had to go to dinner.
What I meant was position and momentum. The particle through space causes gravity waves which are collected by a detector all around the particle. The magnitude and the direction of the gravity waves given off are inputted into a 3 dimensional computer model and it determines the position and velocity. And what I meant was "Won't" this make the Heisenberg's Uncertainty Principle an old theory? As in once it has been accomplished. PerfectDark |
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#5
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I think gravity waves would themselves be subject to the uncertainty principle, and there will be a limitations on how accurately you can measure it.
A similar situation will arise if you shoot a particle into a magnetic or electric field, causing it to radiate electromagnetic radiation (photons). You can measure the radiation without direct interaction with the particle, but the measurement accuracy of the emitted photon is limited by the uncertainty principle. |
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#6
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scr4 if gravity waves exist then they will be distortions of space-time, not particles. Which I don't think comes under the uncertainty principle.
PerfectDark |
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#7
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#8
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http://www.gravity.pd.uwa.edu.au/ http://igec.lnl.infn.it/cgi-bin/browser.pl http://gravity.phys.lsu.edu/ |
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#9
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#10
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rimshot |
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#11
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#12
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It has been a long time since I passed quantum mechanics but I think that something is not being understood here. The position of a particle is defined by the solution to its time-independent wave function psi. The momentum of the particle is related to the frequency of this wave function. the position of the particle is related to the position of the the wave packet.
If a particle has infinitely precise position, then its wave function would be described by a dirac function. But there is no frequency associated with a dirac function. This leaves the momentum infinitely unknown. Likewise, if the wave packet were stretched over infinite space so that its frequency were precisely defined. It's location would be infinitely unknown. There is no way around this. It doesn't matter how the measurement was taken. Perhaps you should define the properties you are attributing to this hypothetical graviton you are attempting to describe. It may be easier to explain why your theory doesn't work if we know what it is. |
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#13
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As far as measurements go, gravity waves don't give you anything that light doesn't. To measure the position of an object to within some precision delta, you need waves of wavelength about delta or less. Short waves have high frequency, though, which means high energy and momentum, so when a particle interacts with such a wave (either by absorbing it or giving it off), its momentum changes greatly. It turns out that if you multiply the resulting uncetainties, you get the Heisenberg principle (or worse... Waves might not necessarily be the best way to measure a particle). This holds for any waves, electromagnetic, gravitational, or otherwise.
__________________
Time travels in divers paces with divers persons. --As You Like It, III:ii:328 |
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#14
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To add on to others posts (and not repeat what's already been said), we should also note that gravity waves are hard to detect. The detector experiments are trying (and so far failing) to detect the gravitational effects of galaxies, stars, and planets.
The gravitational influence of a subatomic particle (even a very massy one, say a top quark), is amazingly tiny in comparison. It is a huge understatement to say that the experimental errors would tend to mask the actual data. Even in a future with reliable gravity detectors, they aren't going to be using them in particle physics experiments. |
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#15
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That's not a tau neutrino in my pocket; I've got a hadron. |
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#16
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As Christopher basically said:
If the momentum of a particle can be measured with absolute precision the particle does not, inherently, have a position and vice versa. It has nothing whatsoever to do with the measurement process. |
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#17
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It depends on how you look at it.
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#18
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Okay, so I'm kind of a scientific kook around here, I got some crazy ideas. Here's my take on HUP.
I think that the reason HUP holds up in common studies is because we can, so far, only measure certain variables of a particle's characteristics. Because all the aspects of a particles characteristics are not known, being measured, or even measureable by modern science, we cannot accurately determine it's exact velocity and position. I would wager that the HUP begins to break down when you near either absolute zero or absolute one*. The reason for this is simple, the closer to zero energy that a particle has, the less variables are influencing it's actions and position, because they all become 'zeroed' out as we near AZ, and a variable with a value of zero can be ignored. The problem with hitting AZ is that the particles in question disappear when we get there!** So we're limited to about 3 thousandths of a degree above AZ, which still leaves us with quite a few variables to work with, however at this point enough have been eliminated that we can get a 'pretty good estimate' which isn't exact, but hell, it's pretty good. Of course, measuring the P/V of a particle at near AZ is pointless, why would you need to?*** This would also apply, then, at AO, because every variable is at or approaching AO, which means we know all of them and then measuring them becomes unnecessary. However, at this point, we don't know what AO is. --Tim *Absolute One being the highest possible value of every variable acting on a particle. The 'opposite' of AZ, if you will humor me. **My speculation on this is that once all the particle's variables are zeroed out, the particle can no longer exist. It has no characteristics! How could it? ***Of course, at this low of a temperature, the variables are all so near zero that they become quite similar, in fact, if you look at a spectrograph of the atoms in question, their characteristics are so close as to be completely indistinguishable from each other. And this is millions of atoms we're talking about! |
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#19
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Rubbish joke for the day
killall -HUP gravitywaved
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#20
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PLD, Pleonast... a million thank-yous for the updated info. I'll add it to my personal knowledge vaults for later use (probably when the info will be out-of-date again...
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#21
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It's worth pointing out that the Uncertainty Principle is not just postulated, and its proof is not limited to the hand-waving "if you hit a particle with a photon..." ideas with which it is usually explained. Rather, the UP is a mathematical consequence of the operator description of quantum mechanics, arising from the non-commutivity of the position and momentum operators and the mathematical descriptions of uncertainty (there are probably other proofs as well, but this is the one I'm familiar with). If a situation were found where the UP did not hold, there would have to be some rather deep flaws in the basics of quantum theory.
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#22
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Homer, I usually talk myself out of commenting on your posts, because I really don't want to discourage you. Who knows, maybe you'll someday come up with a breakthrough insight.
However, I'm doing it now. First, many variables don't have a 'highest possible value', so your concept of Absolute One makes no sense whatsoever. Second, try to learn a bit more about the uncertainty relations. You have made the same mistake as the OP, assuming that Heisenberg was just describing the limitations of our technology when it comes to studying particle interactions. In fact, he was showing a fundemental fact of the universe. It is the basic uncertainty of quantum physics that allows virtual particles to exist. Since these ghost particles have such a large part to play in our understanding of physics, we'd all better hope that some future gadget doesn't make the uncertainty principle go away. If it did, we'd suddenly have no idea where the basic forces of nature come from, just when we were starting to get it all nailed down. |
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#23
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Homer, just to add to Saltire's comments:
I think you're assigning too much importance to temperature. Particles don't lose their properties at zero temperature, they simply have no thermal kinetic energy. That's it. However, you raise an interesting point when you say that if the particle's energy were known to be exactly zero, then that would make its velocity exactly known, giving infinite uncertainty in the position. If this were the case, as you cool to zero, your box of particles would disappear. But that's wrong. The mistake is in assuming you know that the energy of a box of particles is exactly zero at zero temperature. Actually, atoms have what is known as "zero-point energy", which is the energy associated with the uncertainty in the velocity. Helium stays liquid even at exactly zero temperature, due to its large zero-point energy.
__________________
http://giraffeboard.com: come for the food, stay for the conversation. (Most of the conversation is about the fact that there isn't actually any food.) |
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#24
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Most of what I have read implies that gravity will be adopted into a quantum framework, not the other way around. I don't think any physicists actively think that the HUP is wrong on some level, it has simply been confirmed in too many experiments.
The HUP has nothing to do with measurement. I think the thing that is most illustrative of this are the "super atoms" that some team of scientists made (unfortunately the article was in my mother's scientific american and she live 10 hours away), otherwise known as Bose-Einstein Condensates. Supercooling atoms to just above absolute zero will indeed make their velocities(momentum) very precisely known. Their position, however, begins to be a bit murky and the effect, if it is done with a pure element, is that all the individual atoms disappear and one "large atom" is made. Others can fill in the necessary details, but the upshot is that the HUP ain't wrong. |
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#25
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I'm just crazy enough to realize it.
![]() Saltire, I appreciate your candor. However, how can we prove that there is not an absolute possible highest value for all variables? Such an idea, at this time, can only be theorized, correct? When I was speaking of Absolute Zero in the sense that reaching it removes all characteristics from a particle, I meant Absolute Zero inclusive of all known^h^h^h^h real forces, not 'just' heat energy. Such a thing would likely be found only in deep space, because we retain magnetic and gravitational influence on particulate matter here on earth. But by all means, in the future, tear my postulations to shreds. Unless I know that they are false, I cannot begin to construct true ones. Giraffe: When cooled to as close as possible to absolute zero, particles do disappear, lending a slight credence to my posulation. Quote:
I speculate that these atoms have become removed from each variable and ceased to exist; their entirety was released in the explosion and absorbed as various energies by the measurment devices. I cannot learn truth unless I also learn what is false. Hence, destroy my speculations so I may rebuild them correctly. ![]() --Tim |
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#26
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Also of interest:
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![]() --Tim |
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#27
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Homer: Blame it on the Bosenova.
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#28
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From "Bosenova" (that's Homer's url)
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About "zeroed-out" variables--in an atom, you can never zero these observables:
Even when an atom is in it's lowest energy state, there are still non-zero forces acting between the parts of the atom. You can't ignore these forces, and they don't ever become zero. |
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#29
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Homer, your ideas are crazy (but I'm reserving judgment on you
). However, the Absolute One idea is interesting. I've never really thought about it before in these terms, but current physics breaks down at the Planck scale. See this thread Planck length question. At some extremely high energy, the wavelength of a particle would be about the Planck length. I'm not sure what it'd mean for a particle to have a higher energy (and thus shorter wavelength). Any particle physicists want to tackle this one?
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#30
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Pleonast, if you'd like to read some of my more out-there ramblings from the height of my stoner-scientist days last semester, please read through this thread. I admit I was rather stoned during the length of it, either while thinking of the ideas or typing them. You should see the stuff I thought too crazy to submit!
I've written up a lot about some stuff, and am trying to organize my thoughts on the four dimensional math model, the repeating -inf,-1...,0,1...,inf cycle, and the law of fours to demonstrate to a physics professor. He'll likely look at me funny then throw me from his office, but it's worth a try.As for the value of AO, I think it's probably Einstein's Constant, but I can't prove it. --Tim |
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