…and I think I understand what the authors are getting at.
In the first paper, they model the Newton’s cradle ball arrangement as a system of discrete springs and masses. They then show that to reproduce the symmetric collision behavior the balls exhibit (i.e., n balls collide from the left, and n leave from the right, with the remaining balls stationary), the spring-mass system must be dispersion-free. By dispersion-free, they mean that the wave speed associated with each natural mode is identical (i.e., no dispersion of [spacing between] the wave speeds).
This makes sense if you understand that in the original collision, all modes are excited. In a dispersion-free system, the portion of the disturbance associated with each mode propagates at the same speed, so it kind of “comes back together” at the same spot, pushing the n right-hand balls. If the system is not dispersion free, wave speeds are different, and disturbances associated with each mode bounce back-and-forth without recombining in an orderly fashion.
For those of you who didn’t read the paper, an interesting experiment is performed: Four air-track gliders of the same mass are fitted with springs. Three are lined up, and the fourth is slid down the track. It turns out that this arrangement is not dispersion-free, and the system scatters. The authors calculate the parameters for a dispersion-free system (different ratios of springs and mass), run an experiment, and it works like a charm.
OK, now the second paper models the real ball-chain apparatus. In this paper, the authors basically say, “forget the first paper, except for the dispersion concept.” They discuss that the “spring” between balls arises from Hertzian contact stresses, which follow the model F=k*x^(3/2), rather than the typical F=kx (like the glider model in the first paper).
Now, here’s the important part: They say that a system of balls, or sliders, with slight gaps between each is dispersion-free (i.e., it will perform like a Newton’s cradle). Since the slope of the Hertzian contact equation F=k*x^(3/2) is zero at x=0, it’s almost like the force is zero for small displacements…kind of like a small gap between the balls. This isn’t perfectly dispersion-free, but it’s good enough, since nearly all of the momentum is transferred to the last ball. The remaining momentum imparts a small velocity to the balls, so that during the second round of collisions, there really is a small gap between balls, and the system is perfectly dispersion-free.
Now, I still have some questions:
- I’ve never heard the term “dispersion-free” before. I wonder if this is some jargon coined by the authors, or if it’s been used in other places.
- The authors never show how “dispersion-free” applies to the system of masses seperated by a small distance; they just state that it is. I can logic out how this works, I think, but it still seems to be a gap in the paper.
- The authors never really prove that a dispersion-free system is either necessary or sufficient for the symmetric behavior shown by the Newton’s cradle. They offer a plausible explanation, which I suppose is good enough for me, but they don’t prove it.
- Their model shows that, for a five-ball Newton’s cradle with one ball dropped, the fourth ball has 12% of the velocity post-collision that the first one did pre-collision. This seems kind of high: anyone out there up to some observational experimentation?
- In their conclusion, the authors say that a 40 micron gap between balls is sufficient for dispersion-free reaction. The chart they refer to clearly shows four microns. Maybe a typo, but in a followup response paper by the authors [AJP, Vol. 52, p.84], they give a figure of 20 microns. Which is it?
Oh, good job on the research, Cal. These papers were a pretty interesting followup to the mailbag item.