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#1
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can you cancel out light in the same way noise cancelling headphones work?
Noise canceling headphones work by creating an audio wave with opposite phase to the noise you are hearing. Does this work for light? If so that would let you "project dark" which would be great for increasing contrast on projectors and have lots of applications in the AV world.
I suspect that if this is theoretically possible the problem is that computer chips and projection devices can't switch fast enough to match the waveforms that they sense so no canceling is possible in practice. Am I right or is this not even theoretically possible? |
#2
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You have to remember that light acts as both a particle and a wave. The eyes do their sensing by absorbing the particles (photons). So you can block those by closing your eyes or wearing a mask.
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#3
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It is theoretically possible, but in practice, not even close. It could be done with radio frequencies.
But remember that the noise cancellation effect is beyond the headphones. If there were a material which was a perfect reflector for audio sound waves, they could just use that. For light, there is; you could just put aluminum foil to block out the light you don't want. |
#4
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What I'm asking is can we create a light canceling projector that works by detecting the photons in a space and projecting light with same frequency and opposite phase. |
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#5
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You can certainly create interference patterns with light where the opposing peaks and valleys of the waveforms cancel each other out. But I can't think of how you could create a light-canceling device. It would take time to detect the waveform and calculate it's opposite and since the signal is moving at the speed of light any opposing waveform your projected would never be able to catch up.
Last edited by The Hamster King; 10-17-2009 at 12:20 PM. |
#6
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#7
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It's not the reaction time of the human visual system you have to worry about; it's the reaction time of the light itself. The period of visible light is about 10-15 seconds, so you'd have to react faster than that to be able to achieve any cancellation at all. You could, in principle, anticipate what the light wave is going to do before it does it, and cancel it out that way, but that would only work with an extremely consistent source like a laser, not something like the Sun or a light bulb.
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#8
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#9
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#10
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Actually, I should point out that there are systems which can and do react to light fast enough to cancel it out, but such systems are precisely what an opaque wall is. The incoming light excites the electrons in the wall in just such a way that the light wave on the far side of the wall is canceled out, and there's a reflected light wave on the near side of the wall.
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#11
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But such a machine could, I think, still be effective if the light source wasn't changing very much. |
#12
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The other major obstacle is the short wavelength of visible light.
Even with sound it is difficult to do cancellation unless you have one of two situations: 1) The source of the noise is highly localized and you can put a cancelling transducer within a fraction of a wavelength of the source. 2) The place where you want to recieve the audio is very localized and you can cancel the noise within a fraction of a wavelength of the reciever. Case 1 is the basis for some commercial machinery which is made quieter by active noise calculation. This is usually working at low frequencies with large wavelengths. The one situation where case 2 works really well is headphones. The wavelegth of middle C is about 4 feet. The highest frequency you can hear has a wavelength of about an inch. The headphones are placed precisely with respect to the reciever (your ear drum) and within a fraction of a wavelength over the audible band. Light has a wavelength of a fraction of a micron. |
#13
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I suspect coherence would be an obstacle too.
What if the device split the light in two, then let one path travel 1/2 wavelength further than the other before it recombined? Of course it would only work at one wavelength. |
#14
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You don't need to catch up with light. You can expect your light source to be emitting light with the same properties into the next nanosecond.
With coherent, monotonal light (ie, a laser), it is trivial. But actual light has an enormous mix of frequencies, and each source has its own phase (and i'm not sure, does polarity count too?) I think it could be done, but the amount of information ('bandwidth' in the technical sense) involved is huge. Can someone calculate it for us? It would be terabits, no? Audible sound is kilobits, maybe megabits. And that is just for one point! For sound, you've got 2 point receivers. For light, you'd have to do it at each pixel. |
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#15
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I don't think it's possible even in principle for an incandescent light source, like an old-fashioned light bulb or the Sun, and it might not even be possible in principle for spectral-line sources like fluorescents or LEDs.
Oh, and the words you were using should be "monochromatic", not "monotonal", and "polarization", not "polarity". |
#16
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#17
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#18
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For a laser, sure, you could do that, and in fact something like that is involved in most practical applications for lasers. For a non-laser, though, 1/2 of which wavelength? A light bulb produces light at all wavelengths. At best, you'll filter out a few specific wavelengths, but everything else will get through.
On thinking about it some more, you could pull it off for any monochromatic source, but it'd be a lot harder for a non-coherent source. |
#19
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Optical interference is readily observed in oil films and insect wings. The colors you see are partly due to selective cancellation of specific wavelengths of white light, and partly due to selective reinforcement.
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#20
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The trick would be to use metamaterials - engineered materials with a negative refractive index. You could create a mirror where light reflects on the back along the incident path, with a shifted phase. Current metamaterials are far too frequency/wavelength specific to allow general solutions, but in the future...
Metamaterials may help with the response time issue raised earlier, too. Remember that the limit of information propagation is c, the speed of light in a vacuum, and that the speed of light in air is somewhat lower (0.9997c). Metamaterials may have a speed of light faster than that of air, so you can get information ahead of the in-air wavefront, but given the small percentage differences in velocity, you could only do this over a long distance. The better solution (for the OPs posited projection) is to engineer better screens, using metamaterials that have high reflection over a narrow incident/wider viewing angle, and zero reflectivity for other incident light. Work has begun on metamaterial traps that have zero incident reflectivity (for microwaves currently) that direct all incident radiation into the center. This will be ideal for energy capture (ie solar) but super-black materials are a possibility over a wide range of angles. Si |
#21
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It's tough to produce interference effects between two independent light sources -- as others have noted, you need to have two sources coherent, which has in the past meant that both rays have generally come from the same source, with the path length difference relatively short. Paul Dirac was convinced that you wouldn't see interference between two light sources, and said so in his book on Quantum Mechanics.
Then in 1963 Mandel and another guy demonstrated that you could, in fact, get interference between two different light sources, and published the result in Natuyre (vol. 198, pp. 255-6). Lots of people have done it since, usually with lasers (Am. J. Phys. vol. 61 242-5 1993, for example) I still don't think it's "easy", though (I've never seen it myself). I don't know that it's been demonstrated with anything except highly coherent sources and under very strict circumstances, and (as been pointed out above) the sort of device the OP asks for would like it to work over a broad range of colors and with "natural", low-coherence light. I seriously doubt that you're ever going to get this to happen. Even for a limited viewing area and range with ambient light I doubt you'll ever see it. Lippmann photography is a useful effect that uses a broad range of colors with natural ambient light, and it requires very special equipment and treatment because the ranges over which the interference effects occur is so damned small. In a way, it's the closest analogue to what you're asking about You see, sound waves are easy to generate to produce coherent effects, and have a long coherence range, and can work over a broad spectrum of wavelengths -- all exactly the opposite of light. |
#22
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![]() Since your an optics kinda guy, I thought this might interest you. Back in the 60s, early 70s?, some astronomers used IIRC what was called intensity? interferometry to measure apparent size of the largest stars. Optically, its nothing like you expect when you talk about interferometry. Nothing precise about it. They had big moveable "telescope" mirrors mounted on a railroad track. The mirrors were crap precision wise, just giant light buckets. At the focus were just photometers, no imaging was involved. They did some kind of correlation thing with the photon noise to measure apparent angular size of the sources. They wrote a short book on the story, how they did, and the results. When they proposed it, there were a fair number of optical experts that were sure it could not work even in theory, much less practice. The non math, non theory parts of the book make for an interesting read of "science drama". Its a neat little book, and if our modest library had it, it cant be too hard to dig up. |
#23
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On the other hand, my dad walked in when I first got the coating on a pair of glasses, and said, "magnesium fluoride". So it does seem to be the same stuff used on telescopes. Wiki backs up the destructive interference idea, http://en.wikipedia.org/wiki/Anti-reflective_coating. Why then do telescopes use it? Wiki mentions getting better contrast through not getting "stray light", but I can't picture this. I couldn't explain why or how this works to a bright high school student of mine. |
#24
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Cardinal and billfish -- no time now; busy day. I'll answer, if no one else does, but not until much later, maybe tonight.
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#25
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The two cent answer is two part.
First, many optical surfaces need to be coated with something "tough" because they are "delicate". Second, when you make a simple coating that causes destructive interference at one wavelenght, it cause constructive interference at another. So, for a telescope/optics system, you make the coating so that it causes more of the light with a certain wavelength you want to get through. Like say the wavelength of light your sensor is most sensitive to. And sometimes you design a coating to NOT pass a specific wavelength. |
#26
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Of course you would need a very smooth mirror and very sensitive mechanics to get a few hundred nanometer slope in the mirror. Peizoelectrics can get that type of sensitivity in AFM and the mirror could be as simple as gold deposited on mica. |
#27
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Most glasses have a refractive index of about 1.5. If you put down a layer of material for which the thickness multiplied by the refractive index of that substance is a quarter of a wacelength, you will get destructive interference at normal incidence. (The ray travels twice through the material, so it travels a half a wavelength between the time it enters the layer and the time it leaves after being reflected) The ray that travels through the layer is half a wave out of phase with a ray that simply reflects from the surface, so the amplitdes add, and cancel out. Bingo -- you have reduced the strength of the overall reflected beam by making a beam that bounces off the surface of the Mag Fluoride and the ray that passes into the mag fluoride and reflects from the glass underneath very nearl cancel out. For the most efficient cancellation, you want the refractive index of your coating material to be about the square root of the initial medium (air, with an index of 1, for practical purposes) times the square root of the underlying glass (about 1.5, as i say). The refractive index should this be about 1.225. For Mag Fluoride it's 1.38 in the middle of the spectrum, which is close enough. Mag Fluoride is also tough, which is worth using even if the refractive index isn't a perfect match. Of course, this will only work for one wavelength, but you choose the thickness so that the wavelength is close to the middle of the visible spectrum, and live with the reflections from other wavelengths. This is about the easiest anti-reflection (AR) coating you can do. It only requires a single thickness of material. Typically, coating engineers design "multi0layer stacks" that use multiple coatings of different materials, usually alternating a high and low refractve index. The more layers you use, the better you can extinguish reflections and the broader the spectral region you can cover, or the sharper you can make the cutoff. As for Stray Light, using such an AR coating will reduce this only because it reduces reflected light. Stray Light is generally handled by using apertures and special coatings on telescope walls, which has nothing directly to do with coating. Quote:
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#28
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Cal. I know that. I know that you know about that too. The interferometry I was referring to WAS NOT phase based, at least in the commonly understood sense of the term. It used basically giant shaving mirrors on railroad tracks for pete's sake. If it was that crude how COULD it posssibly be phase based when working in the visible/near visible range ? IIRC it was intensity based. I could be loosing my mind, but I don't think its something most people think of when they think of interferometry, particularly these days. |
#29
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#30
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Do you mean that the coatings on the walls are unrelated to those on the lens? Second, is the AR coating is reducing stray light by reducing reflections inside the scope, that might be reflecting off the lens after having first passed through it? |
#31
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Coatings are generally used to prevent transmission of wavelengths you don't want and maximize transmission of wavelengths you DO want. In addition, such coatings should be "clean" and free of scattering, which will contribute to Stray Light. I'm not sure what sense you're using Stray Light in. Quote:
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#32
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Nothing to be sorry about. I was brushing over the obvious non-linearity to make the principles of the device understandable. You would probably have to have some sort of physics degree to figure out what curvatures were necessary to make it work, but nanometer adjustments are comonplace with AFM and nearly atomicly flat surfaces are created daily (also for AFM). I'm just saying that I think it might be plausible if difficult to do. I have no idea if there are other unforseen issues.
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#33
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If you are really interested in this, I can browse the library next week and see if I can find it. |
#34
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As for the other thing I said, I meant, "are AR coatings used to interfere with light that might have bounced back to the bottom of the lens, to eliminate it from reaching the sensor out of phase with the good light, or out of place? |
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#35
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To be blunt about it, the "special coating" you use on the inside of the telescope walls is black paint. Really good black paint, maybe, but it's a fundamentally simpler problem than making something that doesn't produce excessive reflections but still allows light to pass through it, like you need on the lenses.
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#36
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#37
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Before the really fancy black paints, you know what made a good black surface if done right (if I understand correctly) ? A block of razor blades clamped together. |
#38
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Anyway, since I cannot find a site online, you have only my word for it. If we define a parameter, say alpha, as the separation of two apertures (mirrors for the case of your telescope) times the radius of an incoherent source divided by the distance to the source, then the mutual intenisity (and the visibility of the interference function) will fall as J1(a)/a where J is a Bessel function of the first kind. By increasing the distance between mirrors it is easy to find the nulls of the Bessel function and thus determine the radius of the star (as long as you know the distance and have a good wavelength filter - the light needs to be relatively monochromatic). For the sun, the first null of the Bessel function occurs for a mirror separation of ~8 microns IIRC (this is the coherence length of the sun at 1 AU). This effect can be used to create nulling interferometric telescopes. Regarding anti-reflection coatings, all of these rely on interference and the coherence length of the source. For incoherent sources like the sun or light scattered by objects, this length is very small so the coatings need to be very thin. Last edited by Happy Fun Ball; 10-20-2009 at 05:02 PM. |
#39
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[QUOTE=L. G. Butts, Ph.D.;11685017]The telescopes you refer to did use phase (there is no such thing as intensity based interference). [QUOTE]
But like I said, phase not in the "normal" sense of the word when one thinks of interferometry. You mention measuring coherence length by measuring intensity. That is probably what I am recalling. When I think of astromonical interferometry, I think of two telescopes collecting light. You bring that light together in one spot. You optically adjust the optical path differences so that you can control it to a fraction of wavelength of light. It all very optically precise and rather difficult to do. Obviously YOU understand this set up that I recall. But rather crude optics and no high tech correction of optical path differences, much less not EVEN bringing the two light sources together (IIRC) is your grandfathers interferometry, not what most folks think of these days. |
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#40
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The Hanbury Brown-Twiss and related Experiments (warning pdf). What I was remembering was the Michelson stellar interferometer while what you were remembering sounds like the more advanced Hanbury Brown-Twiss interferometer. Both make use of the complex degree of spatial coherence, but the HBT relies only on intensity measurements without interfering the beams. Anyway, good stuff... On another note, I read from your reply that I might have been coming off as an asshole (what with the bolded I and you); if this is the case, sorry, wasn't my intention... |
#41
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No problem ! ![]() Those names you reference ring a bell...its amazing what those old neurons "remember" isnt it ? As for the bolded parts, I was just trying to be more clear...no intended assholishness here on this end (heh). We all remember or learn something new once in awhile dont we ? Though ya know, if you wanna come off as less of an asshole....you need to drop the Butts part of your user name ![]() Seriously though, nobody in this thread has come off as an asshole as far I am concerned...just a little bit of not quite talking the same language....which I am sure I am as much to blame as anyone else here.... Thanks for taking the time to give us your expert input ! Its been a very bad day here for me, so if you cant make heads or tales of me today....forgive me. take care Blll |
#42
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So, if AR coatings necessarily create constructive interference for some frequencies of light, is that noticeable by the eye? My point is that the glasses sales people will say things like, "It helps driving at night." It may emphasize some frequency, but there obviously can't be more photons getting through than were arriving at the surface to begin with. Could it possibly be that these cheap coatings do anything worthwhile in assessment of dark surroundings?
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#43
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