n = 1, t = 0: I move my pen from point 0 to point 0.9 of the number line
n = 2, t = 0.9: I move my pen from point 0.9 to point 0.99 of the number line
n = 3, t = 0.99: I move my pen from point 0.99 to point 0.999 of the number line
…
For every n ∈ ℕ there is a line on the list.
For every n ∈ ℕ is valid that we don’t reach 1.
ℕ is clearly defined as the infinite set of the natural numbers { 1, 2, 3, … }.
Nothing happens after an infinite number of steps. There is no action specified after an infinite number of steps. Not on this list:
t = 0: I move my pen from point 0 to point 0.9 of the number line
t = 0.9: I move my pen from point 0.9 to point 0.99 of the number line
t = 0.99: I move my pen from point 0.99 to point 0.999 of the number line
…
Please present your list which specifies what happens after an infinite number of steps.
The distance is not defined, because the position of 0.999… is not defined.
And this doesn’t matter, because we’re looking at what happens once we’ve done all infinity steps. The result we’re looking for is not present in ℕ. There is no step n, n ∈ ℕ that encapsulates what we’re doing. If we don’t reach 1, then after an infinite number of steps, where are we? What is our distance from 1?
Again, I refer you to the example with the balls in the barrel. It seems like, if we add a net of 9 balls every step, we should have an infinite number of numbered balls. But no matter which number you choose, I can point to the step where we necessarily removed that ball. Infinity is weird and counterintuitive. This isn’t even a particularly weird or unintuitive case; it’s perfectly well-understood what happens at a convergent limit. And you still don’t get it.
Yes, at no discrete step during the “process” do we reach 1. It doesn’t matter - the process can be accurately described as “Getting infinitely close to 1”, and as a result, after an infinite number of steps, we are infinitely close to 1 - meaning that there is 0 distance between 0.99… and 1, and therefore they are the same number.
The entire point of applying a limit in this case is to see what happens after an infinite number of steps. And we do it because looking at the individual steps on the list does not give us the full picture. If we haven’t already finished all of the infinite number of steps, we’re not looking at 0.99…; we’re looking at 0.9999999 or 0.999999999999999999 or even
Which is still a far cry from 0.99… because it doesn’t go on literally forever. And contrary to your assertions, the position 0.99… is very well-defined: it is 3 x (1/3). 1/3 is 0.33… and 0.99… is simply three times that. Or we can use your definition; 0.99… is the sum of the convergent infinite row i(n) = 9*10^(-n). That works too, as long as you don’t blunder right into Zeno’s Paradox and refuse to accept any attempt to resolve it.
The point is: We have finished an infinite number of steps by t = 1. At t = 1 we can state that the only actions are the actions on the list. And according to these actions the state of the pen is pretty undefined at t = 1. It is definitely not at position 1. Unless you present another list of actions.
And by extension 0.333… is also not a number? Lots of eight-year-olds are going to be saddened by this news.
BTW, I think you should have come right out and said all this in your first post
"*what are you talking about 0.999... = 1 is nonsense because 0.999... isn't even a number*".
I, for one, would have saved quite a bit of time.
Ignore actions. They clearly give a nonsense answer, even if you can’t admit it. Continuous motion.
The pen moves from 0 to 10 (just for fun). As it approaches and passes 1 it either passes by a point that can be described as 0.999… or it passes by one with a finite number of 9’s.
If it does pass by 0.999… how large is the distance between that and 1? I’m not waiting for your answer, as I’m sure it’s that the distance is not defined and that you’re going to reiterate your step by step process which everyone else understands traps you in non-mathematics.
My position was clear from the very beginning:
The distance |1 - 0.999…| is undefined, because the position of 0.999… on the number line is not defined.
You’re wrong. 0.99… is well-defined, and it clearly corresponds to a point on the number line. Interestingly enough, you can reach this point by performing the supertask you continue to define: just keep getting infinitely closer to 1, until after infinite steps, you have 0.99… and you also have your position on the number line: 1.
netzweltler, I am sure I am not the only one who isn’t convinced that your arguments are made in good faith.
You have side-stepped issue after issue and have showed no preparedness to play the game and argue directly to the points made. I feel obliged to do some mathematics for you, this isn’t how it should work, you should be doing this yourself.
We’ll suppose that you are right, that 0.999… < 1
If p ∈ (0, 1) then p < √p < 1
So 0.9 < √0.9 < 1 so the first digit after the decimal point of √0.9 must be 0.9
and 0.99 < √0.99 < 1 so the first digits after the decimal point of √0.99 must be 0.99
and 0.999 < √0.999 < 1 so the first digits after the decimal point of √0.999 must be 0.999
It should be obvious that as 0.999… is an infinite string of 9s, that its square root must also be an infinite string of 9s.
i.e. 0.999… = √0.999…
What number(s) are there for which x = √x ?
There, no deltas, no epsilons, no limits as n approaches infinity. High School maths at most.
There have been many interesting posts from BPC and others, but the didactic exercise is obviously a waste of time at this point. It’s not as though this is a student who wants to learn something. Just like relativity cranks and creationist cranks, he’s a mathematics crank who’s just going to keep repeating his misconceptions and ignorance of mathematics ad nauseum without regard for any explanation that’s offered.
The nice thing about plunging down rabbit holes is there’s a hookah smoking caterpillar to be found.
103rd …
Then please state the definition you are using in the following, because (…) can be defined as a long comma … requiring the reader to pause a bit longer than a comma but not so long as would be the case with a period.
Again, infinity is not a natural number … so asking us to pick a line n (∈ ℕ) is nonsense … it is your process that is flawed … as well as your definition of a number … and of course your logical assumption that infinity is just a very large finite number is wrong … your citations are absent … you seem to have difficulties with basic addition … long division is just too far “out there” … and that you should say that anything about mathematics should be “ill-defined” show a lack of even the simplest of understanding on the subject.
Take the pill and go through the little door, take the next pill and jump over the fence, second door on the left … have a few puffs if it is lawful for you to do so in your jurisdiction.
My final advice to you is to bring more humility with you when you log on to the message board. Here, there are professionals in most all the fields of human endeavor. So when someone with an advanced college degree in mathematics weighs in on a question about mathematics, you’d be wise to respect that information. Try to be more appreciative of their time explaining things.
Actually, here’s where you’re wrong. In your model, at t=1, then pen has “jumped” an infinite number of times, and has come to rest on 1.0
So far, you’ve declared that it doesn’t…but you have never actually demonstrated this. If you’d actually, y’know, do the math, you’d realize where you’ve blundered.
By the way, what is the square root of 0.999~? And are you able to construct a proof by contradiction, beginning with the assumption that 0.999~ does equal 1.0? You seem to enjoy cutting and pasting your same old dreary goop over and over, but you don’t seem to have any willingness to engage in actual constructive mathematics.
The exercise about putting balls into and out of a box is an unnecessary distraction from this thread, since it’s discontinuous, and so the limit isn’t meaningful. The limit for 0.9, however, is perfectly well-defined.