Here was my reasoning: Expectation where X is one draw is is 0.5. The expected value of two draws is 0.5+0.5 = 1. Since the casino will draw until the sum is greater than 1, three draws are more likely than not, and you should play.
Here was my reasoning: Expectation where X is one draw is is 0.5. The expected value of two draws is 0.5+0.5 = 1. Since the casino will draw until the sum is greater than 1, three draws are more likely than not, and you should play.