No. You just have to shed entropy if you want to form something at a lower entropy. A gravastar has lower entropy than a “normal” star, so you need to shed entropy (and a lot of it, in this case). A black hole has higher entropy than a normal star, so you do not need to shed entropy. What the entropy of a gravastar implies about its temperature, I do not know.
As for the tidal forces: What I said is valid for any gravitating object. Tidal forces are proportional to M/R[sup]3[/sup]. Since a black hole’s or gravastars radius is proportional to its mass, the tidal forces at the surface are proportional to 1/M[sup]2[/sup]. It happens that for a stellar-mass black hole, this leads to tides sufficient to squish humans, but that’s not because of the event horizon specifically. Make your hole (or gravastar) big enough, and you can make the tides at the surface as small as you like. This is not true near the center, however: As you approach the singularity, tidal forces get arbitrarily large, and you’re guaranteed to be ripped apart before reaching the center.
*By extending the concept of Bose-Einstein condensation to gravitational systems, *a cold, compact object with an interior de Sitter condensate phase and an exterior Schwarzschild geometry of arbitrary total mass M is constructed.
With no thermal emission the GBEC remnant then would be both ultracold and completely dark.*
So the temperature of the gravastar is considered to be an ultra-cold object, which would agree with the massive shedding of entropy.
*The shell with its maximally stiff eq. of state p = pc^2 , where the speed of light is equal to the speed of sound could be expected to produce outgoing shock fronts when struck.
The spectra of gravitational radiation from a struck gravastar should bear the imprint of its fundamental frequencies of vibration.*
I’m not absolutely sure I follow this. Can anyone explain ?
Okay, so it is agreed that a gravastar would shed entropy. That sounds a like a minus for the theory to me. I am trying to be open-minded about it, but it really does seem much more likely that a phenomenon like this should increase in entropy in this situation (as a black hole would).
So what is the supposed mechanism by which this entropy is shed? I can only imagine that there would need to be some sort of powerful explosion in the collapse process. That doesn’t sound very reasonable to me.
Can anyone come up with a reasonable description of where this entropy would go after the collapse?
But gravitational waves require changes in gravitation. If we are stationary relative to a collapsing star, gravitational changes would only be a local phenomenon. Thus, I don’t think gravitational waves could carry entropy out of the system.
Neutron stars are created in supernovas. Now that is certainly an explosion capable of carrying away a great deal of entropy.
This whole entropy thing is beyond me. I read a few comments between a couple of really smart guys (John Baez was one) that got different results trying to calculate entrophy gain or loss from a cloud of dust condensing to a star. If they’re a bit confused, I’m just clueless.
*The shell with its maximally stiff eq. of state p = pc^2 , where the speed of light is equal to the speed of sound could be expected to produce outgoing shock fronts when struck. *
How can the speed of light be equal to the speed of sound ?
The speed of sound in a material is affected by, among other things, the stiffness of the material. The speed of sound through diamond is 35 times the speed of sound in air for example. So in a gravistar, apparently the stiffness of the shell would be so great that the speed of sound would be equal to (or nearly so) the speed of light. In hunting around a bit, I found that this property is one of the things that is used to place an upper limit on the mass of a neutron star. Above a certain mass the speed of sound in a neutron star would exceed the speed of light. Since this is not possible, neutron stars above a certain mass can be excluded.
What this means is a potential way to distinguish between gravastars and black holes. When matter hits a gravastar, it would ring it like a bell, except that instead of sound, we’d be “listening” to it using gravitational waves. Further, the exact way in which a gravastar rings would be unique to gravastars, so if we “heard” one, we’d be able to tell that it was a gravastar. The first gravitational wave detectors are just now starting operation, with several more planned over the next few decades, so this is a reasonable way to detect them (I’m not sure what sort of detector would be necessary, though).
Spherically-symmetric collapse cannot produce gravitational waves, but outside of textbooks, the collapse is never perfectly spherically symmetric. In fact, we expect collapsing stars to be a major source of gravitational waves. I think it’s a bit naive, though, to make it a law of nature that collapse cannot be spherical, so as to provide an entropy-release mechanism. As soon as you can come up with any mechanism which would produce a black hole rather than a gravastar, Occam tells us we should just drop gravastars pending further evidence (such as hearing one ring).
Because of their intense gravitational fields, two nearby black holes would attract each other like magnets. They would collide with great fury, and some small fraction of their masses would be converted to gravity waves. The detectability of these cosmic collisions from afar will depend on just how much energy is released. But this detection is bizarre in that it involves sensing distortions wherein space gets momentarily shorter in the direction of the wave.