Curvature of the Earth as viewed at altitude

Surely seeing the horizon as an uninterrupted circle, something most people don’t get to see when on the ground, would be evidence of the curvature of the earth.

It’s a circular horizon, not an infinite plane.

Just seeing something like that, from a height, would appear different to the flat line of horizon we’re used to, even when in the middle of the ocean.

An ant standing on the surface of a bastetball would look around and see the horizon as a line which circles around his head, 360 degrees. This is Joe Average, who is standing in the middle of that field in Kansas.

From the perspective of another ant sitting a few feet away, the same ball would be percieved as a small circle formed by the outline of the ball.
Imagine Laika the dog, looking at the Earth from his rocket window, mourning the borsch he’ll never taste again.

Joe’s horizon actually *would *appear to curve - If he was to take a photo of his view, and he was to hold a straight edge against the picture, he would be able see that the horizon does actually curve downwards at the edges of his photo, if only by an almost inperceivable amount.

This curve should be present for every observer with an unobstructed view of the horizon, (except perhaps for someone resting their eyeballs exactly at sea level), but it would become more obvious at greater altitudes, to the point where some pilots (and perhaps the occational stuntman or space pooch) may begin to notice it with the naked eye.

The only difference is that from very high up you can see it all simultaneously while lower down you need to turn your sight. The view is basically the same. The difference is more psycological than actual.

As an exercise I have calculated the distance to the horizon as an angle from the earth’s center and the height of the horizon above vertical both as functions of observer height above the surface. I have used the radius of the earth = 6371 Km.

The first column is the height of the observer above the surface expressed in Km.

The second column is the angle (in degrees) formed by the lines drawn from the observer and from the horizon, both to the center of the earth.

The third column is the height of the horizon from horizontal also expressed in degrees. The complement of this quantity to 90º is called in navigation the “depression of the horizon” (from the horizontal, defined as perpendicular to vertical).

        • Height Km - - - - angle aº - - - - height of horizon º


000000.002     00.045     89.955
000000.003     00.052     89.948
000000.004     00.060     89.940
000000.005     00.070     89.930
000000.006     00.080     89.920
000000.008     00.092     89.908
000000.011     00.107     89.893
000000.015     00.123     89.877
000000.019     00.142     89.858
000000.026     00.163     89.837
000000.034     00.188     89.812
000000.046     00.217     89.783
000000.061     00.250     89.750
000000.081     00.288     89.712
000000.107     00.332     89.668
000000.143     00.383     89.617
000000.189     00.442     89.558
000000.252     00.509     89.491
000000.335     00.587     89.413
000000.445     00.677     89.323
000000.591     00.780     89.220
000000.785     00.900     89.100
000001.044     01.037     88.963
000001.387     01.195     88.805
000001.843     01.378     88.622
000002.449     01.589     88.411
000003.255     01.831     88.169
000004.326     02.111     87.889
000005.750     02.433     87.567
000007.641     02.805     87.195
000010.155     03.233     86.767
000013.496     03.726     86.274
000017.936     04.294     85.706
000023.837     04.949     85.051
000031.679     05.702     84.298
000042.101     06.569     83.431
000055.952     07.566     82.434
000074.360     08.712     81.288
000098.823     10.027     79.973
000131.335     11.535     78.465
000174.543     13.261     76.739
000231.966     15.232     74.768
000308.281     17.476     72.524
000409.702     20.019     69.981
000544.490     22.888     67.112
000723.623     26.103     63.897
000961.687     29.675     60.325
001278.073     33.601     56.399
001698.547     37.860     52.140
002257.353     42.406     47.594
003000.000     47.167     42.833
003986.971     52.042     37.958
005298.646     56.911     33.089
007041.849     61.641     28.359
009358.550     66.107     23.893
012437.422     70.200     19.800
016529.214     73.847     16.153
021967.166     77.008     12.992
029194.151     79.681     10.319
038798.745     81.892     08.108
051563.158     83.686     06.314
068526.939     85.120     04.880
091071.640     86.251     03.749
121033.330     87.134     02.866
160852.127     87.817     02.183
213770.923     88.342     01.658
284099.492     88.743     01.257
377565.482     89.049     00.951
501780.879     89.282     00.718
666861.943     89.458     00.542
886253.082     89.591     00.409 

It can be seen that you have to get upwards of 1000 Km to be able to see the entire horizon simultaneously but even at 100 Km one can see enough of it to appreciate the roundness of the earth. And even at ground level you can see it. It is just a matter of degree and it slowly increases over the entire range of height. There is no definite transition point.

By the way, you can easily simulate the view using Google earth if you know the right distance to put your eye from the screen. This depends on the resolution of each display.

It will not look like curvature to you, but you can see the curvature of the earth as you sit on the beach for half an hour on Lake Superior watching a freighter sail away (or for geographically challenged people, as you sit on your stoop in Saskatchewan for a day watching your dog run away).

The object eventually sinks below the horizon. What you are seeing, but not perceiving as a curve, is the curvature of the earth.

Always remember and never forget is that elevation is on earth is relative to the center of the earth and line of sight is not. If you forget this and don’t balance you shot lengths, your level run will not close and you’ll have to go out and do it over. And that sucks on a cold wet day.

I’m convinced that this is the effect. You only start to notice that around cruising altitude of commercial flights, around 10 km altitude.

What you are seeing is not the curvature of the earth, but the effects from it or an illustration on how it works.

This post has been brought to you by your friendly GQ Pedantic and Nitpicking Department.

never mind

When I was a boy, I observed the curvature of the earth when on a clear day I looked at the skyline of Toronto from across the lake some 30 miles away. It was obvious that all I could see above the horizon were the tall skyscrapers of down town.

Do you mean that if you were to continue to back up, would you then only be able to see the very tops of the buildings in the skyline?

Thus, not really being able to “see” the curvature of the earth on the x axis, but proving it’s curvature is perceivable on the y axis?

Based on image alone, to get a sense or impresion of the curvature of the Earth, all that is required is to see enough of the horizon that you can see that it starts to bend. This is certainly possible from a building or low plane, maybe even from a beach on the ocean.

Now to directly sense the curvature, we have to talk about our binocular vision, which gives depth perception. It should be possible to calculate the height from which a flat circle is distinguishable from a spheroid section by nature of paralax alone.

I agree with your first paragraph, but stereoscopic vision has nothing to do with the horizon. The maximum range for that is around 10 meters, everything above is perspective, motion parallax and so on.

I agree stereoscopic vision has nothing to do with the horizon, just with depth perception. But I didn’t realize that depth perception ends at 10 meters. I guess ignoring the horizon, one would have to depend on perspective cues. If an Earth sized sphere were covered in a grid, at what distance would the fact the the lines are diverging from parallel be noticable?