Yes, but what I’m trying to show is that one can always create a context, this seems to be the debatable point. As well, the context isn’t that negative numbers exist, its is in what we are calling opposite.
I was basically trying to get to: of all the sets created by taking elements of two other sets (which are the properties of the two objects) in every permutation one will create, as well as all the permutations of those sets, etc, until one has built the largest set without repeated elements from the original two sets (whew!) that everything intuitively that can be compared would be compared. This is the arbitrary context: it always exists (which was what to be shown, halfway). Now I need to find out if in between any two objects, in this general sense, there exists opposties. That is, can we always create a context wherein a given relationship holds.
:shrug:
spiritus
The definition of context I read seems to imply that both you and I are right as to what it means… you may use something like a “frame of reference” or “grouped by quality.” It is the interrelations of things.
You then go on to say that there is neither a “normal” way to define opposite nor can we create a context that contains an opposite. I disagree completely, since those two ideas together seem to make no sense (in any context ;)). If there is no normal way to define it, since it is, indeed, embedded in the idea of context itself (as a corallary, almost), then it seems to me that we can indeed always create a context that contains an opposite.
Putting it into a rigorously logical context seems pretty tough, but the result is damn intuitive to me.
Also, you might note that 2 and negative 2 do not mathematically have the same number of qualities. Negative two is not a natural number.
kabbes
the ^ operator, as defined here, is not provable. You may consider the additive inverse property in algebra, which guarantees (axiomatically) the existence of an additive inverse, such that
For all a there exists the additive inverse of a, written -a, such that a + -a = 0.
AFAIK this is never proved.
In rereading this response so far, I seem to get the feeling for something here, especially now that you, kabbes, have made things a little more visual for me. That is, we are merely defining a new operation.
It is intuitively, and provably, true that one can make a context such that all things are equal (mathematically, if one allows division by zero every number equals every other number).
It seems very intuitive that out of any context one can create a new context which allows for oppositeness. It would be akin to showing that, under some form of valuation, a != b. So long as a!=b, there is some context for oppositeness of the form A/~A, or that [quality of]a + [quality of]b = 0, where [quality of] is the new context.
That is, we are not just comparing color, but the brightness of the color, or the saturation of the color, etc…we keep the original context and enhance it.
Let us take a small example, comparing 2 to 3. In what way are they “opposite”? Let’s use A/~A oppositeness.
We compare 2 to 3 by creating the set (context) of some mathematical qualities (only some for brevity of typing).
2 : {even, prime, element of N,…}
3 : {odd, prime, element of N,…}
Let us create all combinations of sets. Somewhere in there we find {even, odd}.
Our original context was properties of individual numbers. We’ve now created a new context, parity in this case. We now want to find if ~even = odd for A/~A oppositeness.
Note we have not lost any original context, merely added more context on, or made the context more strict. The original context is still there. That is, the property of the property of the property of…these two numbers is opposite.
So, for ~even=odd to be true, every number must be either even or odd. An even number is defined by 2n, where n is a natural number. An odd number is defined as 2n+1, where n is a natural number.
Assume 2n=2n+1, that is, assume that there is some number n where the final number is both even and odd.
2n = 2n+1
-2n -2n
0 = 1
So, obviously there is no number n which results in a number which is both even and odd. I am not about to use the induction to show that every number is either even or odd, however, over N. I think we all know that.
So, we’ve created a context where 2 is opposite to 3 in a A/~A way.
It seems almost trivial that one may always do this by word length, mapping the alphabet onto the number system and adding, etc, to get to a situation similar to this. I lack the notation to write this out. Does anyone disagree, or is anyone disatisfied?
Am I talking out of my ass?