Doubling energy - is it so easy?

You are right, I’ll try stop drinking.

I thought that H2 burns at a temperature between 1000-2000 C. Something similar to Space Shuttle’s liftoff.

Yes, hydrogen burns pretty darn hot. That doesn’t change what I said in my previous post: if you use that energy to produce a breeze for high-altitude windmills to generate electricity, then that energy is not available for the combustion power plant to produce electricity. You can’t use that energy in both places.

What if the windmill or somekind of paddle wheels were inside the damn pipe?

Refer to my earlier posts: if you take energy out at point A, it will not be available at point B.

entropy is important when considering a process or machine. every process is inefficient and each transition contributes to that loss.

That’s the second law of thermodynamics. The OP has yet to fully comprehend the implications of the first law, so I wasn’t even going to try getting into the inefficiencies that are inherent in each step.

I recalculated the potentional gravitational energy of one mole of water and found out an error (a big one) in the original schema. I was using 18 for watermolecules mass - it is 0,018. So instead of double it’s way off.
I might as well face the fact that these fancy pills will not double my penis’ size and forget the lifetime free membership for the spa at the great Lake of Western Sahara.
Thanks anyway.