# Fast cars and downforce!

**URL:** <https://boards.straightdope.com/t/fast-cars-and-downforce/284847>\
**Category:** Factual Questions\
**Created:** [January 15, 2005, 8:45am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847 "2005-01-15T08:45:10Z")\
**Posts on this page:** 7\
**Page:** 1

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**Author:** ![Roadruner](https://avatars.discourse-cdn.com/v4/letter/r/3d9bf3/32.png) [@Roadruner](https://boards.straightdope.com/u/Roadruner)\
**Post date:** [January 15, 2005, 8:45am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/1 "2005-01-15T08:45:10Z")

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HI  
The other day my girlfriend and I were watching one of those educational channels on satellite. The program was about super road cars. She was very interested in all that very expensive hardware that I could never afford so; though she could understand most of the English commentary I would explain the rest to her. Came to the point where the guy on TV said that this particular car weighed “X” and the ground force it generated was “X+” so you could drive it upside-down. She thought about this for a moment then national pride kicked in and she said “In Bangkok there they do this, in a big round thing they drive upside-down, before have only motor bike but now have car”. Erm! Yes and I tried to explain to her the difference between centrifugal force and ground force. But this got me thinking has it ever actually been done? Has some one actually driven a car upside down, on a roof of some sort solely dependant on down force generated by the cars own aerodynamics? 🙂

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**Author:** ![Shalmanese](https://avatars.discourse-cdn.com/v4/letter/s/45deac/32.png) [@Shalmanese](https://boards.straightdope.com/u/Shalmanese)\
**Post date:** [January 15, 2005, 12:37pm UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/2 "2005-01-15T12:37:05Z")

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But downforce is dependant on velocity and maintaining that velocity requires a certain amount of friction between the tires and the road. For it to drive upside down, it would need the excess downforce to be sufficient to maintain the velocity without wheel slippage.

In a sense, it becomes a giant aerofoil right?

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**Author:** ![Xema](https://avatars.discourse-cdn.com/v4/letter/x/9de053/32.png) [@Xema](https://boards.straightdope.com/u/Xema)\
**Post date:** [January 15, 2005, 4:21pm UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/3 "2005-01-15T16:21:16Z")

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> [@Shalmanese](#):
>
> For it to drive upside down, it would need the excess downforce to be sufficient to maintain the velocity without wheel slippage.

Good point.

On a real race car, the aspect ratio of an airfoil would necessarily be limited by considerations of maximum width. I think we can thus assume that the ratio of lift to drag would not be better than 4:1. So if we have a 1000-lb racecar running upside down, at least 250lbs of traction force would be needed to generate the down- (or perhaps I should say up-) force necessary to offset the weight of the car.

To this must be added the normal drag of the vehicle and the downforce necessary to allow traction for that, and the induced drag that results from that additional downforce.

If we assume our hypothetical car (rightside up, in a straight line) can do 180mph while its engine produces 700hp then (based on the equation power = force \* speed) we can calculate that the traction force needed for this is 1458 lbs. A further assumption is that a realistic maximum coefficient of friction for tires is 0.8.

If all this is valid and my calcs are correct, the car will run upside down under the following conditions:  
Speed: 180 mph  
Traction force: 2575 lbs  
Downforce: 4469 lbs  
Power required: 1236hp

This looks as if it would be quite difficult, but not necessarily impossible.

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**Author:** ![Roadruner](https://avatars.discourse-cdn.com/v4/letter/r/3d9bf3/32.png) [@Roadruner](https://boards.straightdope.com/u/Roadruner)\
**Post date:** [January 16, 2005, 10:23am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/4 "2005-01-16T10:23:59Z")

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Right I get the math’s, well in principal anyway and given enough down / up force the tires would have enough traction. I have often heard the aerofoils on racing cars described as upside-down wings like on an airplane. So my guess is that given enough speed a car could fly “upside-down” on the roof of something. It would have to be a tunnel of some sort where the car could get up speed on the ground and then gradually sort of corkscrew up the walls till it was on the roof. But the question remains has it ever been done ??? Could be a stunt for the next James Bond movie. 🙂

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**Author:** ![Princhester](https://avatars.discourse-cdn.com/v4/letter/p/3e96dc/32.png) [@Princhester](https://boards.straightdope.com/u/Princhester)\
**Post date:** [January 16, 2005, 10:41am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/5 "2005-01-16T10:41:08Z")

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Search on this topic and you will find that it has been discussed to death in this forum. I don’t think anyone found any examples of it being done.

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**Author:** ![Princhester](https://avatars.discourse-cdn.com/v4/letter/p/3e96dc/32.png) [@Princhester](https://boards.straightdope.com/u/Princhester)\
**Post date:** [January 16, 2005, 10:53am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/6 "2005-01-16T10:53:49Z")

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Seeing as how you’re a guest, I’ve done the search for you.

> **[Indy cars and anti-gravity](https://boards.straightdope.com/sdmb/showthread.php?t=250163)**
>
> I don’t like Indy racing (Le mans and WRC fan myself) but I like to read up about all cars’ technology. It’s often claimed that Indy cars generate so much down force from their spoiler and their body shaping that they could drive against...

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**Author:** ![Roadruner](https://avatars.discourse-cdn.com/v4/letter/r/3d9bf3/32.png) [@Roadruner](https://boards.straightdope.com/u/Roadruner)\
**Post date:** [January 17, 2005, 10:27am UTC](https://boards.straightdope.com/t/fast-cars-and-downforce/284847/7 "2005-01-17T10:27:13Z")

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Princhester: Thanks for the pointer. Don’t know where that thread came from cos it was not there when I posted my original question, but as you say that just about covers it all. 🙂
