# Help with drug addiction

**URL:** <https://boards.straightdope.com/t/help-with-drug-addiction/543735>\
**Category:** In My Humble Opinion\
**Created:** [June 19, 2010, 1:09am UTC](https://boards.straightdope.com/t/help-with-drug-addiction/543735 "2010-06-19T01:09:21Z")\
**Posts on this page:** 2\
**Page:** 3

<div class="post-metadata">

**Author:** ![Ace309](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/ace309/32/1050_2.png) [@Ace309](https://boards.straightdope.com/u/Ace309)\
**Post date:** [July 17, 2010, 6:36pm UTC](https://boards.straightdope.com/t/help-with-drug-addiction/543735/42 "2010-07-17T18:36:53Z")

</div>

I’m glad to hear you’re doing well, **LouisB** , and I hope that you continue to find support here.

---

<div class="post-metadata">

**Author:** ![ivan\_astikov](https://avatars.discourse-cdn.com/v4/letter/i/58f4c7/32.png) [@ivan\_astikov](https://boards.straightdope.com/u/ivan_astikov)\
**Post date:** [July 17, 2010, 6:38pm UTC](https://boards.straightdope.com/t/help-with-drug-addiction/543735/43 "2010-07-17T18:38:22Z")

</div>

> [@Ann\_Hedonia](#):
>
> It may not be a deliberate troll, but it’s a really bad idea.  
> If you are talking about a situation that involves sick as a dog hard-core withdrawal, then do it with medical help.
> 
> Otherwise…if you have that small stash, you will be fighting your impulses all the time…if the temptation isn’t there it will be easier to resist.
> 
> If you keep the small “just in case” stash, you will hit it really soon, and chances are one of the things you will do once you are under the influence is get yourself a large stash.
> 
> It’s an attitude thing, you’ve quit, you’re drug-free and drug free people don’t keep stashes of drugs. Maybe you will slip but it’s best not to make it too easy.

As someone who quit a 17 yr amphetamine addiction exactly this way, I’m only suggesting what I know for a fact worked in my case. YDrugMMV.

[Previous page](https://boards.straightdope.com/t/help-with-drug-addiction/543735.md?page=2)
