# How far would I fall in 1 second?

**URL:** <https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177>\
**Category:** Factual Questions\
**Created:** [November 22, 2005, 12:29am UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177 "2005-11-22T00:29:43Z")\
**Posts on this page:** 20\
**Page:** 2

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**Author:** ![David\_Simmons](https://avatars.discourse-cdn.com/v4/letter/d/9de053/32.png) [@David\_Simmons](https://boards.straightdope.com/u/David_Simmons)\
**Post date:** [November 22, 2005, 10:00am UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/21 "2005-11-22T10:00:44Z")

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Please, pleeeaze ignore my pervious post. Tevildo is correct. It does work. My excuse? It’s early in the morning.

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**Author:** ![Madd\_Maxx](https://avatars.discourse-cdn.com/v4/letter/m/5f9b8f/32.png) [@Madd\_Maxx](https://boards.straightdope.com/u/Madd_Maxx)\
**Post date:** [November 22, 2005, 3:23pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/22 "2005-11-22T15:23:41Z")

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While everyone else here is obviously smarter about the math here, Why am I the first to ask why you would jump off the 3rd floor balcony in the first place?

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**Author:** ![Q.E.D](https://avatars.discourse-cdn.com/v4/letter/q/51bf81/32.png) [@Q.E.D](https://boards.straightdope.com/u/Q.E.D)\
**Post date:** [November 22, 2005, 3:31pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/23 "2005-11-22T15:31:00Z")

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> [@Madd Maxx](#):
>
> While everyone else here is obviously smarter about the math here, Why am I the first to ask why you would jump off the 3rd floor balcony in the first place?

Because the big, angry boyfriend just got home. 😃

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**Author:** ![DooWahDiddy](https://avatars.discourse-cdn.com/v4/letter/d/e9bcb4/32.png) [@DooWahDiddy](https://boards.straightdope.com/u/DooWahDiddy)\
**Post date:** [November 22, 2005, 3:32pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/24 "2005-11-22T15:32:10Z")

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I feel like I stepped into a thread where I clearly don’t belong, but I’ll ask anyway: If you fall at 32 feet per second per second, then why don’t you travel 32 feet during the first second, not 16?

I swear I’ve read every post in this thread and I’m still not getting why it’s only 16, not 32.

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**Author:** ![Folly](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/folly/32/3219_2.png) [@Folly](https://boards.straightdope.com/u/Folly)\
**Post date:** [November 22, 2005, 3:46pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/25 "2005-11-22T15:46:49Z")

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> [@DooWahDiddy](#):
>
> I feel like I stepped into a thread where I clearly don’t belong, but I’ll ask anyway: If you fall at 32 feet per second per second, then why don’t you travel 32 feet during the first second, not 16?
> 
> I swear I’ve read every post in this thread and I’m still not getting why it’s only 16, not 32.

Because 32 ft/s2 is the acceleration due to gravity. If your speed was a constant 32 ft/s you would travel 32 ft in one second. However, the falling guy starts at 0 ft/s and during that second is accelerated up to 32 ft/s (ignoring air).

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**Author:** ![Tevildo](https://avatars.discourse-cdn.com/v4/letter/t/b9bd4f/32.png) [@Tevildo](https://boards.straightdope.com/u/Tevildo)\
**Post date:** [November 22, 2005, 3:47pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/26 "2005-11-22T15:47:33Z")

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> [@DooWahDiddy](#):
>
> I feel like I stepped into a thread where I clearly don’t belong, but I’ll ask anyway: If you fall at 32 feet per second per second, then why don’t you travel 32 feet during the first second, not 16?
> 
> I swear I’ve read every post in this thread and I’m still not getting why it’s only 16, not 32.

Because your speed starts at zero and increases (linearly) to 32 ft/s over that second. After half a second, your speed is only 16 ft/s.

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**Author:** ![N9IWP](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/n9iwp/32/3154_2.png) [@N9IWP](https://boards.straightdope.com/u/N9IWP)\
**Post date:** [November 22, 2005, 3:49pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/27 "2005-11-22T15:49:17Z")

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You start out at 0 fps. At the end of one second you are travelling at 32 fps.  
The distance you travel HAS to be less that 32 feet.  
Look at it this way. Start at 32 feps and DON’T accelerate. The distance travelled is 32 feet. If you start out slower, obviously you are going to travel a shorter distance.

brian

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**Author:** ![Q.E.D](https://avatars.discourse-cdn.com/v4/letter/q/51bf81/32.png) [@Q.E.D](https://boards.straightdope.com/u/Q.E.D)\
**Post date:** [November 22, 2005, 4:01pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/28 "2005-11-22T16:01:41Z")

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> [@DooWahDiddy](#):
>
> I feel like I stepped into a thread where I clearly don’t belong, but I’ll ask anyway: If you fall at 32 feet per second per second, then why don’t you travel 32 feet during the first second, not 16?.

Despite a previous post, it’s much easier to understand if you look at your average velocity. If you start at zero and at the end of one second, you are travelling at 32 feet per second, then your average velocity during that second was 0 + 32 / 2 or 16 feet per second. Thus, by definition, you have travelled 16 feet during that second.

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**Author:** ![panamajack](https://avatars.discourse-cdn.com/v4/letter/p/47e85d/32.png) [@panamajack](https://boards.straightdope.com/u/panamajack)\
**Post date:** [November 22, 2005, 6:22pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/29 "2005-11-22T18:22:13Z")

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Just to clarify one thing – you aren’t “falling at” 32 ft./s[sup]2[/sup] as that implies a speed (e.g. falling at 120 miles/hr). As has been explained, this is the rate at which your speed changes; your acceleration.

Suppose I have a rocket car. It accelerates at 50 miles/hr per second. Starting at 0 mph, if it speeds up, it won’t travel 50 miles in the first second, but it will be going 50 miles an hour after one second has passed.

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**Author:** ![Bytegeist](https://avatars.discourse-cdn.com/v4/letter/b/9dc877/32.png) [@Bytegeist](https://boards.straightdope.com/u/Bytegeist)\
**Post date:** [November 22, 2005, 6:56pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/30 "2005-11-22T18:56:14Z")

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> [@Tevildo](#):
>
> Yes, it does.

Well crap, you’re right. I didn’t think on it carefully enough — and me an ex-physics major too. How embarrassing.

Never mind then.

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**Author:** ![DooWahDiddy](https://avatars.discourse-cdn.com/v4/letter/d/e9bcb4/32.png) [@DooWahDiddy](https://boards.straightdope.com/u/DooWahDiddy)\
**Post date:** [November 22, 2005, 7:24pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/31 "2005-11-22T19:24:36Z")

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> [@panamajack](#):
>
> Just to clarify one thing – you aren’t “falling at” 32 ft./s[sup]2[/sup] as that implies a speed (e.g. falling at 120 miles/hr). As has been explained, this is the rate at which your speed changes; your acceleration.

A-_ha_. There it is then. I distinctly remember being told as a child that “gravity makes things fall to Earth at 32 feet per second per second” and it never left my brain. But thanks to you dispelling that misinformation, and everyone else’s explanations, it now makes sense. Thanks! 🙂

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**Author:** ![Chronos](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/chronos/32/134_2.png) [@Chronos](https://boards.straightdope.com/u/Chronos)\
**Post date:** [November 22, 2005, 9:24pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/32 "2005-11-22T21:24:50Z")

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> [@](#):
>
> … Yeah, it is linear acceleration. You might need calculus to find the specific velocity at one point in time, but not the distance it travels in a given time. It’s a very simple kinematics problem.

You do actually need calculus to derive the formulae. But once you have the formulae (whether from deriving them yourself, or from taking the book’s or the teacher’s word for them), you don’t need calculus to use them.

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**Author:** ![Q.E.D](https://avatars.discourse-cdn.com/v4/letter/q/51bf81/32.png) [@Q.E.D](https://boards.straightdope.com/u/Q.E.D)\
**Post date:** [November 22, 2005, 10:08pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/33 "2005-11-22T22:08:18Z")

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> [@Chronos](#):
>
> You do actually need calculus to derive the formulae. But once you have the formulae (whether from deriving them yourself, or from taking the book’s or the teacher’s word for them), you don’t need calculus to use them.

Right. Which is a good thing, for me. No matter how hard I’ve tried or what resources I’ve used, no one’s been able to explain the _process_ of calculus to me in such a way as to make the light come on. I understand the reasons for needing calculus and I understand the principles behind it, more or less. But when it comes to actually doing it, I’m a total wash. I dunno what I’m doing wrong or how I could look at it to make it clear in my mind, but I’ve given up trying and have decided I’m hopeless at this point. Maybe you really _can’t_ teach an old dog new tricks. ☹

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**Author:** ![David\_Simmons](https://avatars.discourse-cdn.com/v4/letter/d/9de053/32.png) [@David\_Simmons](https://boards.straightdope.com/u/David_Simmons)\
**Post date:** [November 23, 2005, 1:39am UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/34 "2005-11-23T01:39:11Z")

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> [@Q.E.D.](#):
>
> Right. Which is a good thing, for me. No matter how hard I’ve tried or what resources I’ve used, no one’s been able to explain the _process_ of calculus to me in such a way as to make the light come on. I understand the reasons for needing calculus and I understand the principles behind it, more or less. But when it comes to actually doing it, I’m a total wash. I dunno what I’m doing wrong or how I could look at it to make it clear in my mind, but I’ve given up trying and have decided I’m hopeless at this point. Maybe you really _can’t_ teach an old dog new tricks. ☹

I suppose you’ve been through this exercise but I’ll give it one more chance. Example:

Assume the acceleration is constant = a. The acceleration is the time rate of change of velocity.

acceleration is dv(t)/dt = a.

If we integrate the acceleration we will get the velocity, v(t), because the integral of the derivative of a function such as v(t) is just the function itself.

We are now looking for a function whose time derivative is a.

v(t) = a\*t will fill the bill. Why? Well because the time derivative of v(t) is the limit of (vt(t + Dt) - v(t))/Dt as Dt → 0. I used D because I don’t know how to get the Greek capital delta. Dt is a small non zero increment of time.

so the derivative of a\*t will be found by evaluating the limit of the following as Dt → 0.

(a\*(t + Dt) - a_t)/Dt = (a_t + a_Dt - a_t)/Dt = a\*Dt/Dt = a.

When we take the limit as Dt → 0 this is still a and is the derivative of a\*t which is what we wanted.

So the integral of dv(t)/dt = v(t) = a\*t.

The same process will yield the distance traveled although it is a bit more complicated if done this way.

There are formal ways to integrate a and get the answer a\*t directly. Looking the answer up in a table of integrals is easy. Or using mathematical software is even easier.

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**Author:** ![Rysdad](https://avatars.discourse-cdn.com/v4/letter/r/7cd45c/32.png) [@Rysdad](https://boards.straightdope.com/u/Rysdad)\
**Post date:** [November 23, 2005, 3:04am UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/35 "2005-11-23T03:04:24Z")

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> [@Strinka](#):
>
> This is a very _very_ simple Physics problem.

Uh…_hey!_  
And the reason I used the “jumping off the balcony” example was because it was windy and my spit wasn’t falling in a straight line and wind resistance was screwing up my calculations.

So there.

🙂

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**Author:** ![Bytegeist](https://avatars.discourse-cdn.com/v4/letter/b/9dc877/32.png) [@Bytegeist](https://boards.straightdope.com/u/Bytegeist)\
**Post date:** [November 23, 2005, 3:18pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/36 "2005-11-23T15:18:02Z")

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Ripped from [today’s headlines](http://www.washingtonpost.com/wp-dyn/content/article/2005/11/22/AR2005112201207.html), a man, and a naked man at that, leaps to his death from the 8th floor of a downtown Washington building. As yet, no one knows what the h\*ll it was all about.

Computing the duration of his fall and his speed of impact are left as exercises for the reader.

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**Author:** ![scotandrsn](https://avatars.discourse-cdn.com/v4/letter/s/a4c791/32.png) [@scotandrsn](https://boards.straightdope.com/u/scotandrsn)\
**Post date:** [November 23, 2005, 6:19pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/37 "2005-11-23T18:19:53Z")

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> [@Bytegeist](#):
>
> Ripped from [today’s headlines](http://www.washingtonpost.com/wp-dyn/content/article/2005/11/22/AR2005112201207.html), a man, and a naked man at that, leaps to his death from the 8th floor of a downtown Washington building. As yet, no one knows what the h\*ll it was all about.
> 
> Computing the duration of his fall and his speed of impact are left as exercises for the reader.

The edition of the standard Serway college physics text that I had in a class once had a problem that revolved around the old labor song “Drill Ye Tarriers, Drill”, about men doing a blasting job:

> [@](#):
>
> Last week a premature blast went off  
> And a mile in the air went big Jim Goff.  
> Next time payday came around  
> Jim Goff a dollar short was found.  
> When he asked “What for?” came this reply,  
> "You were docked for the time you were up in the sky.”

The question? “What was Jim Goff’s hourly wage?” Show your work.

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**Author:** ![Tevildo](https://avatars.discourse-cdn.com/v4/letter/t/b9bd4f/32.png) [@Tevildo](https://boards.straightdope.com/u/Tevildo)\
**Post date:** [November 23, 2005, 6:38pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/38 "2005-11-23T18:38:53Z")

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> [@scotandrsn](#):
>
> The question? “What was Jim Goff’s hourly wage?” Show your work.

Neglecting air resistance:

Let x = height, t = time for descent.

x = ut + 1/2at^2

u = 0 ft/s  
x = 1 mile = 5280 ft  
a = 32 ft/s^2

5280 = 0 \* t + 1/2 \* 32 \* t^2

t^2 = 5280 / 16 = 330 s^2

t = 18.17 s (to four figures)

Total time of flight = 2t = 36.34 s = 0.01092 hours

Rate of pay = 1 / 0.01092 = $99.09 per hour.

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**Author:** ![DSYoungEsq](https://avatars.discourse-cdn.com/v4/letter/d/c6cbf5/32.png) [@DSYoungEsq](https://boards.straightdope.com/u/DSYoungEsq)\
**Post date:** [November 23, 2005, 11:45pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/39 "2005-11-23T23:45:25Z")

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> [@Tevildo](#):
>
> Neglecting air resistance:
> 
> Let x = height, t = time for descent.
> 
> x = ut + 1/2at^2
> 
> u = 0 ft/s  
> x = 1 mile = 5280 ft  
> a = 32 ft/s^2
> 
> 5280 = 0 \* t + 1/2 \* 32 \* t^2
> 
> t^2 = 5280 / 16 = 330 s^2
> 
> t = 18.17 s (to four figures)
> 
> Total time of flight = 2t = 36.34 s = 0.01092 hours
> 
> Rate of pay = 1 / 0.01092 = $99.09 per hour.

Aren’t you making the (potentially untenable) assumption that there was no elevation change between where he left the ground and where he landed? 😛

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**Author:** ![Chronos](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/chronos/32/134_2.png) [@Chronos](https://boards.straightdope.com/u/Chronos)\
**Post date:** [November 23, 2005, 11:58pm UTC](https://boards.straightdope.com/t/how-far-would-i-fall-in-1-second/332177/40 "2005-11-23T23:58:51Z")

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As well as the even less tenable assumption that Goff’s supervisor was honest, and docked him for the amount of time actually spent in the air. The problem as stated in the book included “State all of your assumptions”.

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