How much structural damage could humanity cause to the Earth?

The previously linked website is filled with amusing writing, but this is notable in my opinion:

“IEDAB’s Geocide Hotline” Man oh man, I wish I could write things this funny. But, it is still early here so maybe I will… later.

This is an overestimate, because to conserve momentum you have to accelerate the earth in the opposite direction, using some of that energy.

If matter is ejected simultaneously in all directions, then the earth maintains its pre-existing momentum/energy level, and all of the energy of the bombs is contained in the ejected matter.

You weren’t seriously thinking of blowing up all those bombs in one single spot, were you? Because that would be a terrible waste.

Yes, it includes the topsoil on top of the oceans, assuming a very broad interpretation of the word “topsoil.” :smiley:

For mass removal from the surface, release mass amounts of supergreenhouse gasses, hopefully something stronger then CO2, also CFC’s to take down the ozone layer. Let the earth heat up which should get it to offgas much of the atmosphere into space. Perhaps solar mirrors could help with that also. This may also have water leave as well.

This may leave a state where there are frequent sever storms, new surface water patterns, reducing ocean levels which would cause some of the lithosphere to shift and crumble. Perhaps the loss of water from the oceans may cause enough pressure on the continental plates to get them to shift, which would be a form of ‘structural damage’.

What would happen if we stuffed all known nuclear weapons into the bottom of the TauTona Mine in South Africa (2.4 miles deep) and exploded them all at once? For argument’s sake let’s assume Bruce Willis is incapacitated.

Not directly related to the question in the OP, but as a point of reference regarding the nuclear option, according to Cecil:

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That should put into perspective how insignificant the damage potential is to the Earth from the world’s nuclear arsenal.

this page gives a formula for estimating the size of the bomb cavity as a function of bomb yield:

R = 55 * Y[sup]1/3[/sup]

Where:
Y = bomb yield, measured in kilotons
R = resulting cavity radius, measured in feet

YamatoTwinkie says the wordwide arsenal is at 5000 megatons, or 5 million kilotons. The equation gives a cavity radius of 9400 feet, i.e. a little less than two miles. Relative to the size of that cavity, the remaining half-mile of overburden doesn’t seem like much; there’s a good chance it would collapse or be blown skyward, leaving a four-mile-deep hole.

Cool. :cool:

Is it, now? This is an interesting question. Consider a single bomb on the surface of the Earth. Say it launches mass m at speed v. Now, if it’s a single bomb, v is reduced because some energy is used to move the Earth.
Would detonating a second bomb at the same time on the other side of the Earth affect v? How? Expanding gases push against the Earth, which doesn’t move this time, so they bounce off and push on the ejected mass instead? Will they be able to catch up to the mass? Seems they’d just be impacted in the Earth.