# I got new tires on my car, but the tire store over inflated them. Is there a reason?

**URL:** <https://boards.straightdope.com/t/i-got-new-tires-on-my-car-but-the-tire-store-over-inflated-them-is-there-a-reason/965904>\
**Category:** In My Humble Opinion\
**Created:** [June 9, 2022, 3:29am UTC](https://boards.straightdope.com/t/i-got-new-tires-on-my-car-but-the-tire-store-over-inflated-them-is-there-a-reason/965904 "2022-06-09T03:29:38Z")\
**Posts on this page:** 1\
**Showing post:** 22

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**Author:** ![Machine\_Elf](https://avatars.discourse-cdn.com/v4/letter/m/82dd89/32.png) [@Machine\_Elf](https://boards.straightdope.com/u/Machine_Elf)\
**Post date:** [June 13, 2022, 11:00am UTC](https://boards.straightdope.com/t/i-got-new-tires-on-my-car-but-the-tire-store-over-inflated-them-is-there-a-reason/965904/22 "2022-06-13T11:00:55Z")

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> [@Chronos](#):
>
> Shouldn’t be quite that much, but in that ballpark. Ambient temperatures will be around 520-530 F above absolute zero, so a change of 10 F is a little less than 2%. A 2% increase from a base pressure of 35 PSI would be 0.7 PSI.

Presumably you’re talking about 35 psi-gauge, but for this math you need absolute pressure: 49.7 psi. 2% of that is 0.994 psi.

Don’t feel bad. I made the same mistake just a few months ago:

> [@Car tire pressure at high elevation](https://boards.straightdope.com/t/car-tire-pressure-at-high-elevation/958063/19):
>
> Actually it turns out I’m wrong because simple math is hard. Ideal gas law says that for a body of ideal gas at constant volume, the pressure and temperature are proportional. This means that you can calculate pressure and temperature changes like this: P1 / P2 = T1 / T2, or P2 = P1 \* T2 / T1 The trick is that all of those values have to be expressed in absolute. So for a tire starting out at 35 psi-gauge, P1 = 35 + 14.7 = 49.7 psi-absolute. And if it starts out at 75°F, then T1 = 75 + 45…

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