If I were in a place with no other gravitational force how long before I would collapse into a star?

Disclaimer: I’m waaay out of my depth here.

Anyway, is that really true? Given enough time wouldn’t the atoms decay to the point where gravity would be the stronger force?

So far as we know, aside from the rare odd carbon-14 or the like (there aren’t enough of them to matter), the atoms that make up a human body never decay. The molecules, though, can, through the processes that we usually think of as “rot”, and if you let that go long enough, you’ll eventually liquify. Once you’ve liquified, then yes, you would puddle into a sphere.

I’m not sure I understand you correctly, but I don’t think that’s right: even a free (i.e. non-interacting) Fermi gas exhibits degeneracy pressure, simply due to the fact that only two particles of opposite spin can occupy a phase space cell of size (Δx)[sup]3/sup[sup]3[/sup] ~ ħ[sup]3[/sup]; so if you’ve got a total volume V, then on average a particle will be localized to about Δx = (V/2n)[sup]1/3[/sup] if you’ve got n particles, which gives a momentum uncertainty of about Δp ~ ħ(2n/V)[sup]1/3[/sup]; so the smaller you make the box, the higher the average momentum, and thus, pressure resisting any further shrinkage. This is the reason even free Fermi gases don’t condense the way bosons do (although some interacting ones do).

::“Shrinkage?!?”::

Carry on.

There are several decay isotopes in the typical human body.

It’s, uh, a technical term…? :stuck_out_tongue:

Yeah, that’s why I said “and the like”. It’s not just C14, but all of the unstable isotopes combined are still a very small portion of the body. The stable atoms are by far enough to maintain the body in a body-shaped solid structure.