# I'll pay for chemistry tutoring...

**URL:** <https://boards.straightdope.com/t/ill-pay-for-chemistry-tutoring/803723>\
**Category:** Marketplace\
**Created:** [December 6, 2017, 5:03pm UTC](https://boards.straightdope.com/t/ill-pay-for-chemistry-tutoring/803723 "2017-12-06T17:03:05Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![Cardinal](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/cardinal/32/4000_2.png) [@Cardinal](https://boards.straightdope.com/u/Cardinal)\
**Post date:** [December 6, 2017, 5:03pm UTC](https://boards.straightdope.com/t/ill-pay-for-chemistry-tutoring/803723/1 "2017-12-06T17:03:05Z")

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I’ll actually send you money via PayPal or Venmo if you like, for good insight on these questions. I got AP Chemistry materials from a long time teacher who even grades the AP test, but I don’t want to bother him with asking for tutoring. So I have some questions on the semester final he gave me that I’m stuck on.

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The Ka for HF is 7 E-4, and Ksp for PbF2 is 4 E-8. What is the approximate Kc for the reaction? 2HF + Pb+2 \<-- --\> PbF2 + 2H- . All are aqueous except PbF2 is solid.

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We have a reversible reaction: 2SO2 + O2 \<-- --\> 2SO3. All are gases.  
All are put in a container so that each has a partial pressure of 1.0 atm. At equilibrium, the partial pressure of the product is 1.33 atm. What is Kp of this process?

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What is the maximum amount of KCl that can be added to a 50.0 ml sample of 0.200 M Pb(NO3)2 solution before a precipitate forms? Ksp of PbCl2 is 1.3 E-5.

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**Author:** ![engineer\_comp\_geek](https://sea3.discourse-cdn.com/straightdope/user_avatar/boards.straightdope.com/engineer_comp_geek/32/504_2.png) [@engineer\_comp\_geek](https://boards.straightdope.com/u/engineer_comp_geek)\
**Post date:** [December 6, 2017, 6:18pm UTC](https://boards.straightdope.com/t/ill-pay-for-chemistry-tutoring/803723/2 "2017-12-06T18:18:01Z")

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**Moderator Note**

If you want to discuss the actual chemistry questions posed in this thread (without discussing the financial compensation offered), please do so in the GQ thread, which may be found here:

[http://boards.straightdope.com/sdmb/showthread.php?t=843957](http://boards.straightdope.com/sdmb/showthread.php?t=843957)