OK, NTG. I get your meaning, but here’s where I have a problem. Just because it’s impossible to write out doesn’t mean that that 1 at the end of all those zeros doesn’t exist. We’re dealing with the pure and inviolate realm of mathematics, which doesn’t mean have all that much to do with the real world. That “1” is a theoretical “1”, but it is there.
Ok, quick follow up. First of all, strike the “mean” in my post. It’s what I get for trying to form coherent sentences when I should be in bed.
Second, the idea that .999… equals 1 just because they’re infinitely close just doesn’t hold water with me. As my Grandpappy used to say, “Close only counts in hand grenades and horseshoes.”
Thirdly, why the hell hasn’t Cecil done a column on this? It’s come up several times in GQ, and it seems to be right up his alley.
How 'bout it Nick and manny? Can we get Unca Cece to weigh in on this?
0.000…1 is not a real number. If you want to stray into non-standard analysis and call it dx, OK, but first you had better have a solid grip on standard analysis where 0.9999… is exactly equal to 1.
Virtually yours,
DrMatrix
“Feynman was wrong.
I understand Quantum Physics completely.
Anybody seen my drugs?” - WallyM7
Silo’s point was a proof that .99… = 1 using the sum of an infinite geometric series. The sum of such a series is a/(1-r), where a is the first term and r is the common ratio.
.999… =
.9 + .09 + .009 + .0009 + …
which is an infinite geometric series with first term .9 and common ratio .1. So
Silo’s point was a proof that .99… = 1 using the sum of an infinite geometric series. The sum of such a series is a/(1-r), where a is the first term and r is the common ratio.
.999… =
.9 + .09 + .009 + .0009 + …
which is an infinite geometric series with first term .9 and common ratio .1. So
.999… = .9/(1 - .1) = 1.
…ebius sig. This is a moebius sig. This is a mo…
(sig line courtesy of WallyM7)
Briefly, the answer it: it depends. Math is a system made up by people. Different ssytems have been made up. In some the answer is yes, in others no. That is to say, either answer will be consistent with the rest of mathematics. i’m not sure what the answer is for the standard model, but I’m sure that there are “nonstandard” models with the alternative answer.
Oops, I should say that one is AS definable as the other. We’re talking about infinity here, so neither 0.9999… or 0.000…01 are truly definable. They are both concepts.
Things are random only insofar as we don’t understand them.
.999… basically, might as well =1 since they are so close.
but realistically in absolutes 1 = 1 and .999… = .999…
In math 1 = 1 and .999… = .999… unless you want to round up at a certain point then it could equal 1 but does not unless you set a rule (such as, lets round to the tenth). If you do not set a rule on which you round up .999… = .999…
But again we say, “well close enough.”
When it comes to absolutes, close do not count.
The concept of infinity, in this case, allows for consistency.
Since we know that 1/3 + 1/3 + 1/3 = 1 (as stated above), then either 3 X (.333…) = 1, OR you simply concede that 1/3 can NOT be represented as a decimal in base 10.
To restate, infinity is a convenient idea that allows us to do math with consistent results.
The brief answer is that it depends. Standard systems of real numbers equate 1 and .999…
On the other hand, there are nonstandard systems that permit infinitesimals and that who distinguish them. Both system are consistent. There is not “true” answer to whether they are equal any more than there is a true answer to where there are 360 degrees in a triangle. it depends on whether you are using euclidean or noneuclidean geometry.
Oh, come on now. I’m a linguistics major who dropped out of sciences two years ago just so I wouldn’t have to do any more calculus, and I STILL know the answer to this one.
There is no such thing as infinity minus one, so there can’t be infinity minus one zeros, followed by one (0.000…01). INFINITY HAS NO END (duh) so you can’t tag a 1 onto the end of it, nor can you deduct a zero from the end of it and replace it with a 1. So you can’t make 0.000…01, so you can’t subtract it from 1, so you can’t come up with 9.999… that is different from 1. So there. Jeez. I thought after I went into the humanities I wouldn’t have to deal with this shit anymore.
Oh, come on now. I’m a linguistics major who dropped out of sciences two years ago just so I wouldn’t have to do any more calculus, and I STILL know the answer to this one.
There is no such thing as infinity minus one, so there can’t be infinity minus one zero, followed by one (0.000…01). INFINITY HAS NO END (duh) so you can’t tag a 1 onto the end of it, nor can you deduct a zero from the end of it and replace it with a 1. So you can’t make 0.000…01, so you can’t subtract it from 1, so you can’t come up with 9.999… that is different from 1. So there.
Also, 9.999… is not an irrational number because it is the ratio of two numbers: 3 and 3. Jeez. I thought after I went into the humanities I wouldn’t have to deal with this shit anymore.
Most would agree that we are at least trying to use standard analysis.
That leaves KarmaComa as a holdout, maybe, but they haven’t posted in a while.
MrKnowItAll, here is something that you may find interesting. Consider the sum of 1/2 + 1/4 + 1/8 + 1/16 + … This is the basis of the old Zeno’s Paradox: to get somewhere, you have to traverse half the distance, then half the remaining distance, then half what’s left, then… how do you ever get there? You do get there eventually, and the sum of all those halves is one. So, obviously, the sum of all those fractions is 1.
By a quirk of algebra, A/(1-r) equals A + Ar + Ar^2 + Ar^3 + Ar^4… Go ahead, try the polynomial division. IF r is less than one, that infinite sum actually behaves quite nicely, and A/(1-r) actually equals the infinite sum. In the case of the halves, A equals 1/2, and so does r, and A/(1-r) equals one, as above. This is a handy formula. If you have the repeating decimal .181818… you can figure out what the fraction is by using that formula. For .181818…, A=.18 and r=.01. That is, .181818… = .18 + .18*.01 + .18*.01^2… Plug A and r into the formula, and you find that .181818 = .18/.99 = 2/11
That works for any repeating decimal. All repeating decimals are rational numbers, and that is the way to find the corresponding rational number.
Oh, come on now. I’m a linguistics major who dropped out of sciences two years ago just so I wouldn’t have to do any more calculus, and I STILL know the answer to this one.
There is no such thing as infinity minus one, so there can’t be infinity minus one zero, followed by one (0.000…01). INFINITY HAS NO END (duh) so you can’t tag a 1 onto the end of it, nor can you deduct a zero from the end of it and replace it with a 1. So you can’t make 0.000…01, so you can’t subtract it from 1, so you can’t come up with 9.999… that is different from 1. So there.
Also, 9.999… is not an irrational number because it is the ratio of two numbers: 3 and 3. Jeez. I thought after I went into the humanities I wouldn’t have to deal with this shit anymore.