If the pressure is high enough, your lungs will be squeezed and potentially damaged, as well as soft tissue damage around any air spaces (sinuses etc).
It’s less bad than sudden decompression, but I would really not want to test out how much less bad it is.
To be crushed, a body needs to be crushable. A body based largely on water is a poor candidate for this, because water strongly resists compressing under pressure.
Some googling suggests that at 1000 atm, water compresses less than 4%.
OK, so if we descend slowly into our bottomless pit, breathing along the way, we should be fine (until oxygen toxicity or nitrogen narcosis kicks in).
Question me this:
The earth is about 6,000,000, 000,000,000,000,000,000 in some unit of measure, Plus or minus some amount.
Gravity pretty much is what / how we come to notice weight. Air or lead, we seem to think in weight units, like pounds or atmospheres.
Now we get into discussions about weight changes as we move in and out from the core of this big , lets call it an iron ball just to add a bit of simplicity so I can even think about this stuff.
Way out in space I weigh pretty much nothing as far as what I feel about my weight.
On the surface of the iron ball I feel like 200 pounds ( well, 300 actually ) well really just call it any number you want.
I go down the magic tube on my magic elevator so that I can live at the center and I once again feel as if I have no weight. I take along an iron ball which seems to not change at all. ( we are ignoring things like temperature, etc., so do go all nerd on me OK? ) The air weighs the same as it did out in space but used less space at the surface and now it is back like it was in space. Right?
Now my magic press makes the earth into a ‘one inch thick,’ round plate with a diameter that just exactly uses up the 6+ a lot of zeros that was the iron ball earth.
So I am at the center of this huge disc in space that is one inch thick and a really big distance across. What do I weigh?
Magically I go stand on the edge of this disc with all of it under my feet. ( Well there is no up or down but I am in a position where it is all on one side of me. I am not in the middle anymore. ( kinda like Kansas ) It is still a one inch thick, big diameter chunk of iron. What do I weigh now as to what weight I feel?
50% compared to the spherical iron ball due to the distance between me and the geometric center of this big, thin mass?
Now apply these answers to the ones about pressure.
If we are in a place where their is a big enough opening to the air around earth, the pressure is not going to change much because of what air itself weighs, right?
We can compress air in a chamber or in a body with a lot of water where we are between the water and the ocean it is contained in, like wise little delicate places in the human body that will flex due to the liquid body being pressed into those places by the water pressure around the non-rigid container. Us. Right?
With a really strong container you can keep the pressure from going higher because the stuff you try to squish it with can’t. Like the water at the deepest place we have.
IMO, we all need to be talking about the same units.
pressure
weight
distance
center of mass
and so on.
IMO, some people are not wanting to adjust to the fact that all this is interconnected so not all things will work in liner progression in one direction the same at all points along that method of defining weight or maybe better described as perceived weight when the stuff that provides the mass which makes the gravity is less & less all on one side.
GusNSpot, most of that post isn’t really coherent enough to tell what you’re talking about. But I think you asked about compressing the mass of the Earth down into a thin plate, and what would gravity from that be like? The answer is that, as long as you’re not too close to the edge, gravity anywhere in the vicinity of the plate is the same strength, and pointing perpendicular towards the plate.
The same as what? A spherical earth? How would that work with large parts of the mass a long way from you compared to a spherical mass?
Would the mass have a N & S pole since it is made totally of iron?
I do not see how the gravitational attraction would be the same as a the spherical shape?
Also, I was trying to get those that think the stratospheric pressure would continue to rise as the open shaft got near the center of the earth is not going to happen.
Any SCUBA diver knows that going to 30 feet or to two atmospheres is a result of water pressure, not atmospheric pressure. Bob up and down to 30 feet all you want, no problem. The pressure of the air is not harming you. Going deeper for longer periods causes gasses to accumulate in the blood and other spaces. This pressure is because of the water, not the atmosphere.
He’s saying that the plate’s gravitational acceleration at the center of the plate is the same as when you’re a quarter of the way to the edge. Assuming the plate has a very large radius. The direction of acceleration will be straight down.
That is not what I asked.
Try it this way.
There is a ball of material that is the size of the earth & the same average density. Can we assume that the “gravitational acceleration” will make me weigh 200 pounds on my cheap scale at the surface?
Now we take an identical ball and use the magic rolling pin on it so that it is as thick as kitchen foil, nice and round & flat and has a very large diameter, umteen thousands of diameter units more than the ball called earth has and the density of the material is the same as Earth ball, it is identical to the Earth ball’s material.
I maintain that the gravity or attraction at one place on the earth ball is the same at any surface point but on foil world the gravity will be different from Earth ball due to shape which is the only difference.
That difference puts large amounts of mass a lot farther from any one point and so I don’t believe that my weight at point x will be the same as any point on earth ball.
If I go 7000 earth diameters away from the earth, my weight as measured with the same equipment is vastly different and that is solely due to the larger distance from the mass. Even if we run a wire from Earth to this point, I do not believe I will then have the same weight, gravitational acceleration, as I do on earth. Too much of the mass is too far away from each other part.
If this is wrong, please explain it so I might understand. Please.