# Logic is meaningless

**URL:** <https://boards.straightdope.com/t/logic-is-meaningless/137554>\
**Category:** Great Debates\
**Created:** [November 19, 2002, 5:15pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554 "2002-11-19T17:15:01Z")\
**Posts on this page:** 7\
**Page:** 13

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**Author:** ![Liberal](https://avatars.discourse-cdn.com/v4/letter/l/848f3c/32.png) [@Liberal](https://boards.straightdope.com/u/Liberal)\
**Post date:** [December 4, 2002, 6:02pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/241 "2002-12-04T18:02:36Z")

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That’s what I love most about Spiritus. He makes people think.

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**Author:** ![erislover](https://avatars.discourse-cdn.com/v4/letter/e/71e660/32.png) [@erislover](https://boards.straightdope.com/u/erislover)\
**Post date:** [December 4, 2002, 8:06pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/242 "2002-12-04T20:06:30Z")

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**Spiritus** , I am looking over your step 2, A-\>A with necessitation as a justification, but I don’t think it applies there as you’ve written it. Necessitation only shows that what we prove _a priori_ is necessary (and when you think about it, one would hope so). That A is the case doesn’t make it necessary.

But, I admit, I cannot think of how else to do it without asserting  
A -\> \<\>A in the first place, after which (as we have shown) it is trivial.

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**Author:** ![erislover](https://avatars.discourse-cdn.com/v4/letter/e/71e660/32.png) [@erislover](https://boards.straightdope.com/u/erislover)\
**Post date:** [December 4, 2002, 11:03pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/243 "2002-12-04T23:03:54Z")

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1. A -\> ~~A
2. (A -\> ~~A)
3. A -\> ~~A
4. A -\> ~~~~ A
5. A -\> ~\<\>~A  
😕 I have been trying this off and on all day and I can get all kinds of possibles, but there’s always a stupid negation I can’t eliminate.

5 is interesting though. It seems that, just like \<\> can be defined as ~~, can be defined as ~\<\>~. The symmetry surprised me, though I don’t know why.

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**Author:** ![Spiritus\_Mundi](https://avatars.discourse-cdn.com/v4/letter/s/c68b51/32.png) [@Spiritus\_Mundi](https://boards.straightdope.com/u/Spiritus_Mundi)\
**Post date:** [December 4, 2002, 11:21pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/244 "2002-12-04T23:21:09Z")

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**erl**  
Hmmmm . . . you might be right. I would have to include classical quantifiers to get that application of necessity. Actually, I might be able to since we start with “the principles of propositional logic”, but that strikes me as a bit dodgy since I know there is great disagreement over how to apply and read the classical quantifiers in modal contexts. Hmmmm . . . I might be right.

Damn, I told you I was no expert. It really should be trivially derivable in just T. Maybe including an existential quntifier is the right way to go, but I get the feeling I am overlooking something else: something outrageously obvious.

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**Author:** ![Spiritus\_Mundi](https://avatars.discourse-cdn.com/v4/letter/s/c68b51/32.png) [@Spiritus\_Mundi](https://boards.straightdope.com/u/Spiritus_Mundi)\
**Post date:** [December 4, 2002, 11:31pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/245 "2002-12-04T23:31:39Z")

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Yes, the symmetry is implicit in the definitional relationship. You can start with either or \<\> as the primitive. (Well, except for some modal forms designed to model actualism, which require both to be primitive: no symmetry, no elegance, no implication of necessary existence.)

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**Author:** ![Liberal](https://avatars.discourse-cdn.com/v4/letter/l/848f3c/32.png) [@Liberal](https://boards.straightdope.com/u/Liberal)\
**Post date:** [December 4, 2002, 11:35pm UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/246 "2002-12-04T23:35:10Z")

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Eris wrote:

> [@](#):
>
> It seems that, just like \<\> can be defined as ~~, can be defined as ~\<\>~.

That is the exact definition of , if I recall.

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**Author:** ![Spiritus\_Mundi](https://avatars.discourse-cdn.com/v4/letter/s/c68b51/32.png) [@Spiritus\_Mundi](https://boards.straightdope.com/u/Spiritus_Mundi)\
**Post date:** [December 5, 2002, 2:54am UTC](https://boards.straightdope.com/t/logic-is-meaningless/137554/247 "2002-12-05T02:54:53Z")

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Well, either one can be defined in terms of the other. Usually, I believe, is taken as the primitive with \<\> = ~~ by definition. But the of th relationship is easily demonstrated:

\<\>A = ~~A  
\<\>~A = ~~~A  
\<\>~A = ~A  
~\<\>~A = ~~A  
~\<\>~A = A

(Of course, **erl** had already given a derivation above, but I wanted to actually solve a trivial derivation for once.)

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