In that case, what do you think of this “proof”?
x = (4+3)/2
2x = 4+3
2x(4-3) = (4+3)(4-3)
24x-6x = 4^2-9
9-6x = 4^2-24x
9-6x+x^2 = 4^2-2*4x+x^2
(3-x)^2 = (4-x)^2
3-x = 4-x
4 = 3
If you’re consistent, you’d make the same objection as before: “…there’s nowhere in the “proof” that any actual value of “4” is used”.
If that’s the way you want to consider it, it’s fine with me. On the other hand, when I see it, I see the symbol commonly used to designate the value of 4, and that’s the way I interpret it. When we multiply both sides by (4-3), I see it as multiplying both sides by the value 1, which is not a problem.
I see no problems until the square root is taken, because throughout the proof, I understand “4” to be a well-understood symbol representing a value. Whether we actually do any arithmetic with that value is irrelevant, that’s still the way I read it–as a value. Same with the symbol “Pi”. I don’t see how you can possibly fault my logic in saying the error doesn’t really arise until the square root is taken.
What if one of your students solved the following problem:
The sum of two consecutive integers is 21. Find the smallest of these two integers.
in the following manner:
Let 4 denote the smallest of the two integers. We know:
4 + 4 + 1 =21
2*4 = 20
4 = 10, our final answer.
Would you congratulate the student for doing the problem correctly, or would you complain over his unorthodox (and potentially very confusing) notation of using the symbol “4” as a variable (or possibly both congratulate and complain)?