And if your watch happens to be stopped, any time at all would satisfy the condition…
Another simple question: How many times faster is the second hand than the hour hand?
60*12=720.
Of course, that one really was simple.
-Ace
- 1:05:27:16:21:49:05:27:16:21:49…
Essentially, there’s a repeating sequence (as long as each term represents units 1/60 the duration of the previous units) that goes 05:27:16:21:49.
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Obviously, the answer is 3,927,272,727,272,727,272.72 (repeat bar) femtoseconds, or 3,927,272,727,272,727.27 (repeat bar) picoseconds.
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Once you’ve got the answer in seconds, multiply it by 10[sup]15[/sup] to find femtoseconds, or by 10[sup]12[/sup] to find picoseconds. Duh!
Any help on my physics problem above? Anyone?
jackelope,
Obviously your method was the best method, but if you wanted to do it the guess and check way, you could plug in x values into the x/c=t equation and then plug in the resulting t values into the y=-c2t^2 equation until the floor of y equaled x+1.
New sig! New sig!
Thanks, jawdirk, that’s another–extremely laborious–way to do it. And come to think of it, I think the “other way” was explained and it included something equally circuitous; that must have been it. And I recall having to explain my way to the class, all of whom had done it the circuitous way. Very strange experience.
So…people tell you that you take things too literally, too, right? jackelope isn’t the only person I’ve heard complain about “friggin English majors” 
Just for the sake of historical accuracy, allow me to point out that Ace0Spades said, “friggin English majors”; jackelope (that’s me) WAS a friggin’ English major. 