# \# Sequence?

**URL:** <https://boards.straightdope.com/t/sequence/234767>\
**Category:** Factual Questions\
**Created:** [March 17, 2004, 2:20am UTC](https://boards.straightdope.com/t/sequence/234767 "2004-03-17T02:20:14Z")\
**Posts on this page:** 6\
**Page:** 2

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**Author:** ![Biere](https://avatars.discourse-cdn.com/v4/letter/b/b9bd4f/32.png) [@Biere](https://boards.straightdope.com/u/Biere)\
**Post date:** [March 17, 2004, 10:09pm UTC](https://boards.straightdope.com/t/sequence/234767/21 "2004-03-17T22:09:41Z")

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> [@ultrafilter](#):
>
> The 5th differences are not constant, so if this is generated by a polynomial, its degree is at least 6.

Had the same problem, I think (???), with question 25 on the Mensa workout page …

[http://www.mensa.org/workout2.html](http://www.mensa.org/workout2.html)

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**Author:** ![dinoboy](https://avatars.discourse-cdn.com/v4/letter/d/65b543/32.png) [@dinoboy](https://boards.straightdope.com/u/dinoboy)\
**Post date:** [March 17, 2004, 10:19pm UTC](https://boards.straightdope.com/t/sequence/234767/22 "2004-03-17T22:19:21Z")

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> [@](#):
>
> Had the same problem, I think (???), with question 25 on the Mensa workout page …

I don’t think so, it seems the patterm is simply adding pairs in that one (1+10=11, 3+9=12…)

The answer should be 11, 5 (for a total of 16)

Now, what did I win? 😃  
As for the OP, I’m still working on it… 😕

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**Author:** ![RayMan](https://avatars.discourse-cdn.com/v4/letter/r/e495f1/32.png) [@RayMan](https://boards.straightdope.com/u/RayMan)\
**Post date:** [March 17, 2004, 11:42pm UTC](https://boards.straightdope.com/t/sequence/234767/23 "2004-03-17T23:42:28Z")

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> [@ultrafilter](#):
>
> The 5th differences are not constant, so if this is generated by a polynomial, its degree is at least 6.

Yeah. I fit a polynomial of degree 6 to this data set and came up with 193 as the next number in the sequence, as I have already posted before. Of course, there is no reason to believe that these numbers were generated by the absurd sixth degree polynomial with rational, non-integer coefficients I derived. Just some pointless math knowledge put to use.

With simple little sequences like these that have no obvious pattern, one can come up with a justification for _any_ number to be the next in the sequence.

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**Author:** ![DrDoom](https://avatars.discourse-cdn.com/v4/letter/d/e19b73/32.png) [@DrDoom](https://boards.straightdope.com/u/DrDoom)\
**Post date:** [March 19, 2004, 10:03pm UTC](https://boards.straightdope.com/t/sequence/234767/24 "2004-03-19T22:03:30Z")

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> [@SwingWing](#):
>
> 4 … 15 … 10 … 9 … 16 … 12 … 13 … Next?

Sum of the digits for 2 times n-1 plus 7 … e.g.

2 x 10 = 20 = 2 + 0 = 2 + 7 = 9 …

Answer is 15. Sum of digits sequences are utilized on Mensa III tests …

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**Author:** ![sibyl](https://avatars.discourse-cdn.com/v4/letter/s/b9e5f3/32.png) [@sibyl](https://boards.straightdope.com/u/sibyl)\
**Post date:** [March 20, 2004, 12:16am UTC](https://boards.straightdope.com/t/sequence/234767/25 "2004-03-20T00:16:11Z")

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I got 15 right off the bat.

4 … 15 … 10 … 9 … 16 … 12 … 13 … Next?

4+15 = 19  
10+9 = 19  
16+12 = 28  
13+x = 28

x = 15

_shrugs_

Wouldn’t know how to get the one after 15 now though, so I guess there is a better way.

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**Author:** ![DrDoom](https://avatars.discourse-cdn.com/v4/letter/d/e19b73/32.png) [@DrDoom](https://boards.straightdope.com/u/DrDoom)\
**Post date:** [March 20, 2004, 12:28am UTC](https://boards.straightdope.com/t/sequence/234767/26 "2004-03-20T00:28:44Z")

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> [@sibyl](#):
>
> I got 15 right off the bat.
> 
> 4 … 15 … 10 … 9 … 16 … 12 … 13 … Next?
> 
> 4+15 = 19  
> 10+9 = 19  
> 16+12 = 28  
> 13+x = 28
> 
> x = 15
> 
> _shrugs_
> 
> Wouldn’t know how to get the one after 15 now though, so I guess there is a better way.

Nice logic! …

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