Thanks for the helpful replies QED, Mort Furd, and billy. I need to do some more reading on that ground loop link, but I’ve only had time for the first page.
I can sum up my misunderstanding pretty easily. In fact, it’s in my first post and Mort Furd’s. I stated (and believed) that there was a very negligible resistance in household copper wire. Mort Furd used 1 ohm in his example. Although he stated this to be worst case, I actually believed it to be off by a factor of 100 if not 1000. A quick check on the resistance of the household copper wire proved my belief wrong. So, since there is a very real and applicable amount of resistance in the wire and the rest of my statement was based on negligible resistance… well, can I have some salt to go with this crow? :smack:
I just wish one of the electricians I talked to would have just said, “resistance in the wire”. Oh well.
As far as sailor goes, I’m not sure that I understand the need to insult me where others are educating. However, to combine what you wrote (Ohm’s law):
with what I was using for values (incorrectly as explained above):
You will get:
V = I * 0
or
V = 0
In other words, no voltage just like I also said. If I’m learning from your example, should I now insult your reading skills?