Ahhh, feathermuck.
We can figure out what the function f(x) = (x[sup]3[/sup]-8)/(x-2) ‘should’ be from the limit, should we want to define it at x=2: since the limit is 12, defining f(2)=12 turns f into a function that is continuous at 2.
It helps that this particular function has a nice, well-defined limit there.
OTOH, when we’re talking about the entire class of indeterminate forms whose numerator and denominator both approach 0 as x gets near to some value, such well-definedness goes right out the window. Each such expression has its own limit (if it has a limit at all), and the values of these limits are all over the place. So as others have pointed out here, there is no single value that 0/0 ‘ought’ to be, hence calculus is no help, except in a negative sort of way - reaffirming our intuition that there’s no appropriate definition for 0/0.