This is true, but you’re no longer working with functions if you do this. Most of why we assume y=sqrt(x) takes the positive square root is because taking both results in a non-function. |y|=sqrt(x) (or even |y|=x) results in the same “problem”.
This is true, but you’re no longer working with functions if you do this. Most of why we assume y=sqrt(x) takes the positive square root is because taking both results in a non-function. |y|=sqrt(x) (or even |y|=x) results in the same “problem”.