If a TV has 16:9 aspect, and the diagonal size is n inches, what is the width/height of the picture?
It’s late, I’ve been fiddling in Excel for 30 minutes on this, and it’s really bugging me. I keep getting something like sqrt((diag*diag) * hiAspect )/loAspect. Not.
!@#!@ing Pythagoras
I hope I’m not presuming to translate for the slightly less geekily inclined.
For the height:
square the diagonal, divide by 4.16, then take the square root of the whole thing.
For the width:
square the diagonal, divide by 1.32, then take the square root of the whole thing.
It’s a close approximation using decimal conversions of the fractions, but it’s a lot easier with a basic pocket calculator and it comes out within a very small fraction of an inch.
Let the sides be 16x and 9x and the diagonal be n. Use the Pythagorean theorem and solve for x in terms of n. Multiply x by 9 to get one side and by 16 to get the other. Since 337 is the sum of 9 squared and 16 squared,
Or, looking at it another way: if one side of the rectangle is 16 and the other one is 9, then the diagonal is 18.36. Any screen with the same proportion will have proportional dimensions: