[QUOTE=Contrapuntal]
Isn’t there a subtle difference between an enclosed truck and the open environment surrounding a bridge? Why is it necessary for the juggled coin to exert force on the bridge? Suppose he were to keep two coins in the air? Would that change anything?
[/QUOTE]
I suppose there is a subtle difference between the two systems, but it doesn’t matter, because it is necessary the juggled coin to exert force on the bridge (ignoring the “clever” answers, like throwing the coins across the bridge, or entering low-Earth orbit, or whatever).
Consider a simplification: the 68kg magician stands on a scale, tossing a single 1kg coin up and down. What does the scale read? While the coin is in the air, the scale will read 68kg (ignoring the magician’s motion). But when the magician catches the coin, he’s got to decelerate it, and then accelerate it back upwards. And, as a basic principle, F=ma. So the scale sees not only the weight of the magician and the coin, but also the upward thrust required to accelerate the coin – the scale sees more than 68+1kg (equivalent force), in other words.
The magician could, of course, accelerate the coin very lightly, to minimize the additional force. But, in that case, the coin is in his hand for a long time, and it’s not in the air very long at all, so the scale shows a little more than 68+1kg for a long time.
Or, the magician could accelerate the coin very firmly, to minimize the time it stays in his hand. But, in that case, the required force is very large, so the scale shows a lot more than 68+1kg for a little time.
Either way, if you go through a time average, you will (I think–I did this once but I’m too lazy to do it again) come up with a total time-averaged scale reading of 68+1kg.