In the game between Tampa Bay and Toronto tonight, the Jays scored 4 runs and struck out four times in the first inning. According to the announcers, this has happened once before in the history of MLB–in 1902.
The first two batters struck out. Then came a single, a run-scoring double, a walk, a three run homer, followed by a strikeout-wild pitch, a single, and a final strikeout.
He’s probably referring to 4 strikeouts and 4 runs in the same inning. A guy pitching well enough to get 4 Ks doesn’t often give up 4 runs unless it’s something crazy like this inning was
Of course; I’ve even seen it once in person. But the team that struck out four times did not also score 4 runs in that inning.
That game I watched on TV, but I’ve seen some remarkable games in person. One (of two in MLB history) that ended in a walkoff unassisted triple play. A perfect game (never saw an ordinary no-hitter). A game that ended in a walkoff hit batsman. And one that ended in a grand slam (although only one run was needed).
So how are four strikeouts in an inning possible? A batter with two strikes on him takes a swing at strike three; however, the catcher does not field the ball cleanly, and instead of tagging the runner out, the runner reaches. The strikeout is recorded, but not the out.
There’s also the very rare occurrence that an umpire loses count of balls or strikes or even outs. Nowadays in MLB that’s not going to go unnoticed before being corrected, but back in the day each of those mistakes has been played through.
I can’t remember who they were playing against but one game I was in attendance, the D-Backs had the Inning That Would Not End. Going through three pitchers, they faced thirteen batters. Needless to say, they lost.
There is in fact no theoretical limit to the number of strikeouts that could be recorded in an inning, if the catcher is particularly inept. However, the most an MLB inning has ever has is four.