Algebra, is it possible to..

solve an equation that is x+x^2=800? I am doing a problem and I can’t get it further than that.

Try subtracting 800 from both sides of the equation and applying the quadratic formula.

Start by re-arranging it as x[sup]2[/sup] + x - 800 = 0.

Yeah, what The Peyote Coyote and Anthracite said. The quadratic formula is easy to find on Google, just in case you don’t have it present.

x+x^2=800
x^2 + x - 800 = 0

ax^2 + bx + c = 0 where

a = 1
b = 1
c = -800

The quadratic formula is

x = (-b +/- sqrt(b^2 - 4ac))/(2*a)

Plugg’n and chugg’n gives you two real answers (rounded to the Eighth decimal place):

x = 27.78869032
x = -28.78869032

I was going to respond to this thread earlier, but I forgot that it existed:) Thanks for the help.