Anyone want to try to solve this riddle?

If you choose an answer to this question at random, what is the chance you will be correct?

A) 25%
B) 50%
C) 0%
D) 25%

Which question? The one in the thread title (anyone want to try to solve this riddle?) or the one in the OP?

That’s interesting…
I guess I’d say “none of the above.”

The one in the op.

B.

Probably none of the above.

It has the smell of the liar’s paradox.

C is supposed to be 60%.

Wait… That wasn’t right. Ignore this post.

There is no correct answer.

A and D cannot be correct because there is a 50% chance that I will pick them but then the correct answer is B.

B cannot be correct because there is a 25% chance I pick it, but then the correct answer is A or D.

C cannot be correct because there is a 25% chance I pick it but then the answer cannot be correct, since I picked it.

OK, I’ll give it a go. Assume each answer in turn is correct (ignoring that the answers are percentages) and then see what the implications of that are (by not ignoring that the answers are percentages).

If A) is correct, then you have a 50% chance of getting it right, since it also means that D) is correct. But if the answer is 50%, then A) isn’t correct, and so neither is D).

If B) is correct, then you have a 25% chance of getting it right. However B) is actually “50%,” so B) can’t be correct.

Similarly if C) is correct, then you have a 25% chance of getting it right. However C) is actually “0%,” so C) can’t be correct.

So, as others have said, “None of the above.”

Or, on edit, what RickJay said.

Yes.

For reference, here’s a correct version:

If you choose an answer to this question at random, what is the chance you will be correct?

A. 25%
B. 50%
C. 60%
D. 25%

Citation, citation.

Ah, beaten to the punch. The OP has the wrong question.

This riddle would be easily resolved if we allow for non-uniform random choices.

Doesn’t matter. If you’re picking uniformly at random, there’s no value you can put in C to make the question answerable.

0%.

The question does not explicitly state that you have to choose A, B, C, or D.

I take it that I am choosing an answer from an uncountably infinite set. 0% is the correct answer, and I might choose it, but nevertheless my chance of choosing it is 0%.

50% would do it, wouldn’t it?

I don’t see this as a reasonable interpretation of what was written.

Yeah, it would. Nice catch.

The options are ‘correct’ and ‘incorrect’.

Remind me to play poker with you some time.