I cannot imagine any property of physics that would account for the earth spinning at 1040 mph at the equator amounting to 1,525 ft. per second would cause a targeting adjustment of only a few inches. A formula can be created; however the contradictions that occur keeps the formula at a stage of unproven theory. Following
is my analysis regarding the Coriolis effect and gravity:
I. If you stand dead center of the North Pole, there is no centrifugal force. It takes 24 hours for one to rotate 360°.
Weights and measures have to be determined where there is no centrifugal force; at dead center of the North or South Pole?
II. An airplane and/or helicopter that is disconnected from earth can land on an aircraft carrier that is a moving target as fast as 1040 mph.
A Cessna 172 that is disconnected from earth at flight speed of 161 mph can adjust for earth’s rotation speed of 1040 mph at the equator?
Two tests of theory & path of totality.
Subject: Gravity makes one gallon of water appear to weigh 8.34 pounds per gallon, regardless of centrifugal force generated by multiple rotation speeds of the earth.
Centrifugal force at the perimeter of the object is determined by how fast the perimeter is traveling and the diameter of the object. For the earth, the centrifugal force is variable as to its diameter; its latitude location. In Dallas, Texas latitude 32.7767 N° the speed of rotation is 863.8 mph compared to 537.4 mph at Olympia, Washington latitude 47.0379° N. These different earth rotation speeds of 863.8 mph and 537.4 mph generate a different centrifugal force on an object. In our case, the object is one gallon of water that appears to weigh 8.34 pounds per gallon both in Dallas, Texas and Olympia, Washington.
In fact, one gallon of water appears to have the same static weight as it runs in a river from north to south across multiple earth diameters (180° of latitudes) and earth’s corresponding multiple rotation speeds. The standard weight of one US liquid gallon of water is about 8.34 pounds at 62° F. There is no adjustment for the weight of water as to its latitude location. Apparently, gravity makes this adjustment for weights and measures.
If one were to believe the conclusion that gravity makes an adjustment for weights and measures to be accurate and that the conclusion can be proven to be true then you have a fact. Otherwise, if there is some other factor(s) that causes one gallon of water at 62° F to be 8.34 lbs. but it cannot be proven, then you have a theory. Is the theory about how to calculate centrifugal force, or is the theory about whether the earth rotates 360° in a 24 hour time frame?
This is quickly becoming complicated. At what latitude is the one gallon of water at 8.34 pounds at 62° F determined? It has to be dead center of the North or South Pole where there is no centrifugal force. At dead center of the poles, there is no diameter or travel speed to consider for the math components of centrifugal force. For the math of Centrifugal Pounds Force, a gallon of water in Olympia, Washington is 12.415 lbs. as opposed to Dallas, Texas at 19.915 lbs. Otherwise, gravity has made all of the math work out to be that water weight is 8.34 lbs. per gallon regardless of its location in lakes, ponds, and rivers running from the north to the south.
There are “Earth does not move experiments”: The Michelson–Morley experiment was performed over the spring and summer of 1887 by Albert A. Michelson and Edward W. Morley …an attempt to detect the relative motion of matter through the stationary luminiferous aether ("aether wind"). The result was negative…the direction of movement through the presumed aether, and the speed at right angles, was found not to exist; this result…eventually led to special relativity, which rules out a stationary aether. The experiment has been referred to as "the moving-off point for the theoretical aspects of the Second Scientific Revolution". Michelson–Morley type experiments have been repeated many times with steadily increasing sensitivity…recent optical resonator experiments confirmed the absence of any aether wind at the 10−17 level.
Bradley’s (in 1725) so-called ”aberration of star light” gave the first experimental disproof of the heliocentric hypothesis. A hypothesis is the starting point for further investigation.
Science cannot be wrong, there surely must be an equation that resolves the conundrum that gravity makes one gallon of water weight be 8.34 lbs. per gallon regardless that earth’s multiple, surface speeds range from 1040 mph at the equator to zero mph at the poles.
Subject: How does a Cessna 172 at flight speed of 161 mph adjust for earth’s rotation speed of 1040 mph at the equator?
In Dallas, Texas latitude 32.7767° N the speed of earth’s rotation is 863.8 mph compared to 537.4 mph at Olympia, Washington latitude 47.0379° N. These different earth rotation speeds are determined from the fact that earth rotates 360° in a 24 hour time frame corresponding to the diameter of the earth at these respective latitudes. In fact, there are 180° of latitudes resulting in earth’s multiple surface speeds ranging from 1040 mph at the equator to zero at the poles.
These multiple speeds are mathematically described as the Coriolis effect (Rotating Earth) for an object that becomes disconnected from earth. Described in “Long Range Shooting Handbook” by Ryan M Cleckner, military snipers have to adjust their sight targeting based on their latitude location as well as the angle of the sniper’s shot relative to his latitude location In an email exchange I had with Mr. Cleckner regarding one parachuting from an airplane, he states “Although I’ve jumped out of a plane many times, I was never in charge of determining the jump point for the drop zone - I can’t speak to how those calculations are made.”
It gets complicated. Degrees of latitude are parallel so the distance between each degree remains almost constant. Each degree of latitude is approximately 69 miles (111 kilometers) apart. Coriolis effect takes into account 180° of latitudes then each half mile, each quarter mile and so on with 360° of angles off each latitude. Does a sniper’s rifle that requires precision targeting have precision GPS? A .30-06 hunting rifle fired due north at the equator has to adjust for earth spin at 1,525 ft. per second. Usually these type rifles are used for taking 350 to 500 yard shots.
The Coriolis effect requires that airline pilots must adjust flight path to reach their target destination. The instrumentation used by airlines is Honeywell: Air Data Inertial Reference System (ADIRS) which includes an Alignment Calibration Module (ACM) for the Coriolis effect (e.g. multiple rotation speeds).
The Coriolis effect is further described and illustrated as an animation on Exploring Earth stating that pilots take the Coriolis effect into account so they do not miss their targets. Exploring Earth states that the analysis is a collaboration with NASA/Goddard Space Flight Center and others (identified at the bottom of the animation web site). View the animation and pay attention, it is misleading. For the animation of south to north - Tierra del Fuego, Argentina directly toward Rio de Janeiro, Brazil – a flight taking an estimated time of five hours, the surface speed of the target destination is 948.5 mph. The target destination would move 4,743 miles; the Earth’s diameter is 7,918 miles.
How did WWII vintage aircraft land on an Aircraft Carrier; how is it done with modern day aircraft? ADIRS supposedly provides calibration for point to point navigation. What happens when a Navy pilot (the aircraft is disconnected from earth) arrives at his Aircraft Carrier destination that is on the equator and the target landing “spot” is moving at 1,525 ft. per second?
Neil deGrasse Tyson has even commented that the spinning earth affects football games; that the Coriolis effect does have to be considered regarding the flight of the football on a field goal attempt. http://www.nfl.com/news/story/0ap3000000555398/article/neil-degrasse-tyson-earths-rotation-helped-cincy-win
Regarding these supposedly known facts, then for the objects that are disconnected from earth, the following must be true:
In Dallas Texas, latitude 32.78° N, rotation speed is 863.8 mph:
- Hover in a helicopter and you will arrive at your (same latitude as Dallas, Texas) Artesia, NM destination in 31 minutes or your San Diego California destination in one hour and 22 minutes.
- A parachute drop of 5,280 ft. (1 mile) descending at an average of 20 mph requires elapsed time of three minutes. The target football stadium moves 43.2 miles.
- A field goal kicked from east to west that has a one second flight time has an increased distance of 422 yards.
In a Cessna 172 at 161 mph for a 300 mile flight for the same longitude of 102.07° W:
- Earth’s rotation speed at Stratford, Texas is 835.4 mph
Flying South to North, from Midland Texas to Stratford, TX; the target destination has moved 1,557 Miles.
- Earth’s rotation speed at Midland, Texas is 884.2 mph
Flying North to South, from Stratford, TX to Midland, TX; the target destination has moved 1,647 Miles.
In reality we know that light aircraft, such as a Cessna 172 that has air speed of 161 mph does not have to adjust its flight path to be on target to its destination, a helicopter cannot hover and reach its distant destination and a parachutist or airplane pilot does not have to hit a moving target. So, do these examples represent the utilization of Einstein’s Theory of Relativity to maintain a fixed relationship to the rotation of earth?
Science cannot be wrong, there surely must be an equation that reconciles between certain disconnected objects that are - or are not - subject to the Coriolis effect. If you decide to search for the formula or create the formula, remember precision is required:
the earth’s multiple rotation speeds range from 1040 mph at the equator to zero mph at the poles and there are innumerable angles off each of the innumerable latitudes.
For this exercise, do not include the curvature of earth. That can be worked on at a later time.
Nikola Tesla explains the preceding conflicts as follows: “Today’s scientists have substituted mathematics for experiments, and they wander off through equation after equation, and eventually build a structure which has no relation to reality.”
Honeywell: Air Data Inertial Reference System (ADIRS)
Determine point to point time and distance
Subject: What is to be gained by those who promote a spherical earth and cover up flat earth?
Perhaps at its initial conception of earth as a sphere there was no conscious decision to gain anything. Now that we have the ability to attempt space travel, governments and academia have so much of their power structure based on solar centric science, no one wants to risk what happens when the truth becomes known.
The August 2017 solar eclipse path of totality was 70 miles wide. A shadow (the path of totality) cannot be smaller than the object (the moon) that causes the shadow. Therefore, the moon is less than 70 miles wide.
And, science acknowledges the moon and sun is the appearance of being the same size. High altitude balloon (130,000 ft.) videos indicate close proximity of the sun to the earth, likely less than 3,000 miles. The sunspot that shows on the clouds is relatively small; the appearance is that the sunspot is the same size as the sun
It is very likely the sun and moon are at the same distance from earth.