If you have a relation R(XY) with 2 attributes, X and Y, and no functional dependencies, which normal form is R in?
My guess is that it’s in second normal form because (XY) is the only candidate key and any attribute A not in (XY) would be dependent on all of (XY) rather than just a part of it. But I don’t think it could be in third normal form without any functional dependencies, right?
Alternately, could you say that there are trivial functional dependencies, and since all FDs are trivial, the relation is in BCNF?