Database normalization question

If you have a relation R(XY) with 2 attributes, X and Y, and no functional dependencies, which normal form is R in?

My guess is that it’s in second normal form because (XY) is the only candidate key and any attribute A not in (XY) would be dependent on all of (XY) rather than just a part of it. But I don’t think it could be in third normal form without any functional dependencies, right?

Alternately, could you say that there are trivial functional dependencies, and since all FDs are trivial, the relation is in BCNF?

Going to give this one bump. Still trying to figure this out.

It meets the definition of 3NF since all its non-pkey attributes are functionally dependent on XY. It just happens that the number of those attributes is zero.

Friedo nailed it.