Deadly Sixes Game: Explain the apparent probability paradox to me

No, it doesn’t. The losing rate remains approximately ninety percent no matter how many rounds occur.

Let me try one more time.

What is the value of this expression: 2 + 3 + X - X

It’s 5.

It’s always going to be 5. It doesn’t matter what the value of X is. X can be 1. X can be 42. X can be 593,277,360,838,276,268,155. X can even be infinity. But the value of the expression will always be 5.

So if a person claimed you can’t know the value of the expression because X might be infinity, that person would be wrong. And if that person said they don’t agree with you that the answer is always 5, they would still be wrong.

If that person said that you can’t determine the value of 2 + 3 + X they would be right. But if they said that means you can’t determine the value of 2 + 3 + X - X then they’d go back to being wrong because the math that applies to one expression doesn’t apply to the other.