Deceptively easy math word problems for high school kids

. . . I came to a junction and there were two guys. One guy always lied and one always told the truth.

Wait, that one isn’t a math problem.

When I first saw that problem, the first thing I did was calculate the circumference of the Earth in feet (~25,000 miles x 5280 = 132,000,000 feet), then divide 1 by the circumference to get 0.000000008 feet (rounded, about 2.3 nanometers), or in other words, impossible with any realistic knife. Upon reading further replies, including yours, I tried it out myself with a tape measure on various circular objects and found that it was indeed possible. Just hard to imagine that such a small relative change could cause such a large gap when distributed over the entire Earth.

Will putting the knife on the ground between two of the members’ feet work?

Most metal bands would kick you in the teeth if you tried.

I’m amazed this didn’t happen til page three. :wink:

The best proof I’ve seen comes from this board. There are no other numbers between .999… and 1. Therefore, they are the same number.

Regardless of whether it is an exam, a recipe, or a programming language that involves numbered lines of code, reading the whole thing before you start does not override the convention that numbered steps or questions are executed in number order.

Upon first reading of the problem, I thought it is not possible. Then I tried algebra. It is interesting to note that C1 & C2 cancels out. That means this will hold true for any sphere, where circumference is increased by 1 foot.

You can ask the second guy, “what would the first guy say the math problem is”?

:wink:

The problem is that you had calculated an irrelevant quantity. The ratio of added circumferential length : existing circumferential length (1 foot : circumference of Earth) has nothing to do with whether you can slip a knife under; the fact that 0.000000008 feet is very small is of no relevance.

Slipping a knife under is a question of the added radius, not the percentage increase in circumference. And as we all know, radius is proportional to circumference, so adding 1 foot to circumference adds 1 foot/(2π) to radius, no matter how big or small the existing circumference is in comparison to 1 foot.

How many doors does a chicken coop have?

2 if it had 4 it would be a chicken sedan

Also, keeping track of units, the ratio 1 foot : circumference of Earth is a dimensionless 0.000000008, not 0.000000008 feet. Which also shows it to be irrelevant; you can’t compare the width of a knife to a dimensionless value.

Could you tell me what you mean by dimensionless here?

Both dimensions are expressed in " foot". When you divide 2 quantities, where both are expressed in foot, the result will be just a number without a dimension.

Example: 300 feet/ 25 feet= 12 not 12 feet.

Ok, thanks. Now I understand.

Look at this book: Aha!: a two volume collection by Martin Gardner.

There are a lot of candidates there, even in the abridged preview version. One tricky problem is on page 70, “Bipeds and Quadrupeds”.

If you see something interesting that is just partially there, I have both Aha! volumes and can supply the missing parts.

Melons are 99% water and 1% "melon"y matter(let us call it pulp) by weight.

A 100 Pound melon is dried in sun for a couple of days.The dried melon is 98% water. What is the weight of the melon now?

50 pounds?

Yes!

What is the product of (x-a)(x-b)(x-c)…(x-z)?
Since one of the elements of the series is (x-x), i.e., zero, the answer is zero…