[QUOTE=zut]
For the most part, yes. I might quibble a bit with the “directly opposite the mouth opening” part, but that’s close enough that it will work for a thought model.
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I’m not sure it’s valid to call this a quibble. If the molecules in question aren’t directly opposite the mouth opening, they must be along the sides, so then what do we disagree about?
Am I misunderstanding your statements? Am I misconstruing your expression of a mathematical truth (the force equals the difference in pressures times the cross-section of the noodle) for an explanation of how it all works? Are you actually in agreement that it’s impossible to push on a rope, but merely dissatisfied with the undefinability of the “boundary area” where I claim the force occurs? Would it help if I agree that the sum of the shear force that I propose absolutely must be the same as the difference in pressure times the cross-section? Just wondering.
[QUOTE=zut]
I would say that a strain gage measuring longitudinal strain will show a difference when the machines are turned on.
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So then where is the strain coming from? How is force being transmitted to the rods? If not from the molecules outside the chambers, which can *only *act in shear, if at all, where?
Do you propose that the vacuum in the chambers is pulling on the rod? That sounds a lot like (I wish I could whisper this, to prevent the inevitable howls from the peanut gallery) vacuum pressure. (No! No! Don’t scream at me, I don’t believe it either! At least, I don’t dare propose it seriously in public.)
[QUOTE=zut]
OK, then let’s run with this thought experiment. Let me propose a parallel one, that you might actually be able to do at your desk: Take a cylinder, say, an unsharpened pencil. Hold it lengthwise between your palms. Now squeeze together, trying to compress the pencil. Would you think there should be strain in the pencil? Now relax. Does that additional strain go away?
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Yes, and yes.
[QUOTE=zut]
Now, instead of your hands, imagine a magic device that increases air pressure on the ends of the pencil, but only on the ends. Will the increase in air pressure increase strain in the pencil? If you turn off the device, will the additional strain go away? If you run the device in reverse and decrease the air pressure at the ends of the pencil, what do you think happens?
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Setting aside the hope that we could resolve this without resorting to magic, I imagine there is a strain exerted on the pencil by the higher pressure air outside the magic vacuums. Since there’s no perpendicular surface for that pressure to work upon, I can only imagine it exerts a shear force on the pencil’s surface at or near the boundary where the pencil enters the magic vacuum.
Hey, if we return to the same position three times, do the rules of chess apply? Do we have to give up and call it a draw?
[QUOTE=zut]
The machine is not physically attached to the rod, and so cannot transfer longitudinal force to the rod (or not much, at any rate). That means that all the forces on the machine do not sum to zero, because the total air pressure is unbalanced. Ergo, a force pushing the machine along the rod.
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I don’t get it. There’s a force pushing the machine along the rod towards the other machine, but how does this force even know the other machine exists if the force isn’t being transmitted by the rod?