Flight and the Conveyor Belt

:confused:

Thats exactly what I said. You must have read my post becuase you quoted it in its entirety. Was there something unclear?

Not really, or at least not a consistent one. Linear acceleration depends only on the net force and mass of the object. Angular acceleration depends on not only the mass and force but the distribution of both of those. If you give me linear acceleration, force and mass I can not tell you what the angular acceleration is. Conversely, if you give me the angular acceleration, torque and moment of inertia I can not tell you what the linear acceleration is.

I also can change the linear acceleration independently of the angular acceleration and vice versa. If they were related I wouldn’t be able to do that.

Look, I am trying to help here. There is no need for the snark. I am sorry if you don’t like the answer but thats what it is. The only time that angular acceleration and linear acceleration are related is when the physical make up of the system does so. By far the most common situation in which they are related is what we refer to as the “no slip condition.” That condition is when the edge of the rotating body (i.e. pulley or wheel) has zero relative velocity to the linear element of the system (i.e. rope or road). Unless one of these relationships exist there is no relation ship between angular acceleration and linear acceleration.

I apologize, r=radius of the wheel, apha=angular acceleration and omega=angular velocity.

Assumptions:

  1. Uniform disk of mass=3kg
  2. No slip condition exists between belt and disk
  3. Conveyor accelerates at a constant rate of 1 m/s[sup]2[/sup]
  4. F=Force from friction, alpha=angular acceleration, a=linear acceleration of disk, v=linear velocity of the disk, omega=angular velocity of disk, r=radius of disk, Ac=acceleration of the treadmill, m=mass of disk, Arel=relative acceleration, I=moment of inertia.

Sum of force in the x direction equals mass*acceleration in x (From Newton’s second law):

F=m*a (equation 1)

Sum of torque around center of mass equals moment of inertia*angular acceleration (From Newton’s second law):

Fr=Ialpha (equation 2)

From assumption 1: I=1/2mr[sup]2[/sup] (equation 3)
From assumption 2: Ac=alpha*r (equation 4)

Definition of relative acceleration:

Arel=Ac-a (equation 5)

alpha=Ac/r (Solve equation 4 for alpha) -----> (equation 6)
Fr=IAc/r (Combine equation 6 and equation 2)----> (equation 7)
F=IAc/r[sup]2[/sup] (Solve equation 7 for F) --------> (equaiton 8)
F=1/2
mAc (Combine equation 8 and equation 3)-------> (equation 9)
1/2
Acm=ma (Combine equations 9 and 1)-------> (equation 10)
a=1/2Ac (solve equation 10 for a) -----------> (equation 11)
Arel=Ac-1/2
Ac (combine equation 11 and equation 5) ------> (equation 12)
Arel=1/2*Ac (simplify equation 12) --------> (equation 13)
Arel=1/2 m/s[sup]2[/sup] (plugging in numbers to equation 13)

You should have probably read the entire thread before composing that long post. There is nothing in your post that hasn’t already been said.

You also might like to state what version of the auestion you are answering. One states that the belt movesbackwards at the same speed that the aircraft moves forwards, the other states (in essence) that the belt moves backwards at whatever speed necessary to keep the aircraft from moving forwards.

Also, your little airspeed formula is wrong, though it is probably a typo:

Airspeed = groundspeed + headwind component

You have it as groundspeed - headwind.

My astonishment at the volume of logical fallacies and flaky physical theories that have popped up on this thread is exceeded only by my suprise at the tenacity with which people will stick to them.

I’m not going to drag myself into a flame war, and probably won’t even post another message after this. In the interests of helping those still genuinely confused by this whole thread, however, I’d like to point out a couple of things:
*

Once you get it you are going to kick yourself. Perhaps this will help:

Imagine a conveyor belt made of ice and a plane with skis. Now what happens?

Doesn’t matter. If you can multiply force infinitely, you can multiply energy infinitely, too.
[/quote]

I understand the physics quite well, thank you. What I do not understand is the nonsensical statement that 100% of a given force can be applied two ways.

It most certainly does matter. Energy is force multiplied by distance. When you change the distance, you change the total energy input, even though the force. Energy changes; force stays the same. That’s the situation in this example.

You don’t understand, really, if you’re confusing force and energy. My argument essentially boils down to F=ma. Your argument essentially boils down to F ≠ ma.

I’ve worked out an example covering this wheel in more general terms in post 169; treis has provided a more specific analysis linked to in post 406. If there’s something there you specifically disagree with, bring it up. Better yet, provide an analysis that shows the force being somehow partitioned into components which provide linear and angular acceleration.

Again, I’d be happy to explain or provide a more detailed analysis if you think steps have been glossed over, but I’m reluctant to spend a lot of time coding something up if you’re not willing to read or discuss it.

Hum. I do believe, for no slip, Ac=alpha*r + a. Otherwise your analysis looks good to me.

You can multiply force infinitely. Just string together as many pulleys or levels as you want. Your force will be multiplied many, many times.

After a good night’s sleep, I do get it – but not in the way you think.

What I get is that the way this question / problem is phrased, you can’t really answer it. You can’t answer it without making some basic assumptions about speed. This is the reason so many people can disagree so vehemently about the answer and still all be right. Cecil sez:

"Your version straightforwardly states that the conveyor moves backward at the same rate that the plane moves forward. If the plane’s forward speed is 100 miles per hour, the conveyor rolls 100 MPH backward, and the wheels rotate at 200 MPH. "

But it’s actually not that straightforward. Speed is always relative to something else. The question involves two different frames of reference – the conveyor belt and the world outside the conveyor belt. What you use to determine the measurement of speed determines how you answer this question in your own mind.

If you decide that all speed will be measured relative to the world outside the treadmill, the plane very clearly takes off, and the question becomes kind of silly. Once you measure the speed of the plane relative to the outside world, the treadmill is completely irrelevant – it can be going 10,000 times as fast as the plane, but the plane will still take off. The plane need only go faster than take-off speed relative to the world (and air) outside the treadmill. Cecil is dead-on in his assessment of the question when interpreted this way.

Cecil notes an alternative interpretation:

“However, some versions put matters this way: ‘The conveyer belt is designed to exactly match the speed of the wheels at any given time, moving in the opposite direction of rotation.’”

He says this is a paradox, but he’s not quite accurate in his assessment of the situation. This language does not automatically imply a paradox. He says:

"This language leads to a paradox: If the plane moves forward at 5 MPH, then its wheels will do likewise, and the treadmill will go 5 MPH backward. But if the treadmill is going 5 MPH backward, then the wheels are really turning 10 MPH forward. But if the wheels are going 10 MPH forward . . . "

The key to the “paradox” here is a constantly shifting frame of reference. Look at how speed is measured here:

“If the plane moves forward at 5 MPH” --> This is relative to the outside
“the treadmill will go 5 MPH backward” --> This is also relative to the outside
“then the wheels are really turning 10 MPH forward” --> This is relative to the treadmill

Cecil sees a paradox because he jumps between two very distinct frames of reference – the world on the treadmill and the world off – while treating them as if they’re both part of the same frame. There need not be a paradox here – the speed of the plane and treadmill relative to the outside world will always be different from the speed of the plane and treadmill relative to each other, as long as the treadmill is moving relative to the outside world. To stay consistent, it should be worded as follows:

If the plane moves forward at 5 mph relative to the treadmill, and the treadmill moves to 5 mph backward relative to the outside, then the wheels are really turning at 5 mph relative to the treadmill, and the plane is moving 0 mph relative to the outside. If the plane accelerates to 6 mph relative to the treadmill, then the treadmill will accelerate to 6 mph relative to the outside world, and the plane remains moving 0 mph relative to the outside world.

The reason, then, that I argued that the plane does not take off is becuase in my mind, I constructed the situation as such: the conveyor belt’s control system tracks the plane’s speed relative to the conveyor belt and increases the the conveyor belt’s speed relative to the outside world accordingly. Until the plane takes flight, it’s resting on the conveyor belt, and its forward thrust is pushing it and its tires along that conveyor belt. If, as the plane moves forward on the conveyor belt, you increase the speed with which the conveyor belt feeds beneath it, the plane doesn’t move relative to the world outside the conveyor belt, and it doesn’t move relative to the air around it. It never takes off.

You might counter this by saying, “Yes, but because the engine is pushing against the air, it doesn’t matter how fast the plane is going relative to the conveyor belt. The plane moves forwards, and its wheels spin really fast.” Ah, but here’s the rub: as the plane’s wheels spin faster, its speed relative to the conveyor belt increases. The tangle here is that people correlate thrust and speed as if it were absolute: x amount of thrust = x amount of speed. Speed vis a vis the conveyor belt probably requires less thrust than speed vis-a-vis the outside world. If 10% thrust pushed us to 100 mph on a stationary runway, 10% thrust might push us to 1000 mph on our moving conveyor belt.

If this doesn’t make any sense, imagine this: you are a man standing on that runway conveyor belt. When the belt is turned off, the plane’s wheels are still. The plane turns on its engines, and the belt begins to move. If you don’t move, you see the plane rolling down the conveyor belt, moving away from you at a given speed (say, 5 mph). You then jump off the conveyor belt, but before you do, you drop a penny where you were standing. Now, you’re standing next the conveyor belt. Your worldview has changed. The plane, which appeared to be moving away from you when you were on the belt, is now standing still. The penny, which was motionless at your feet, is now moving away from you at 5 mph. You have changed your frame of reference.

If, at any point, the speed of the plane relative to the conveyor is faster than the speed of the conveyor belt relative to the outside world, then the plane moves forward relative to the outside world – but at the cost of violating the terms of the problem. The problem states that the conveyor belt’s speed matches the speed of the plane at all times. If you interpret the conveyor belt’s speed to mean “the speed of the conveyor belt relative to an observor standing next to the belt” and the plane’s speed as “the speed of the plane relative to the conveyor belt”, then ouila: the plane never moves relative to the outside observor. If it never moves, it never attains an airspeed greater than zero. The plane never takes off.

So really, at the end of the day, the thought experiment is interesting, but not for the reasons we might think. It’s interesting because it’s a great demonstration of the principle of relativity and its impact on interpreting the world. I, for one, am done trying to argue it – there is no way to ever win the argument one way or another.

I don’t think that’s right. The speed is relative to the outside in all three cases.

I take the “speed of the wheel” to be the instantaneous speed of the point of the wheel which is in contact with the belt.

The “speed of the belt” I take to mean just what it intuitively means, and that this speed is identical to the instantaneous speed of the point of the belt which is in contact with the wheel.

If the speed of the wheel is five mph, then the speed of the belt is 5 mph. Both are speeds with respect to the “outside.” But since the belt’s speed would always add to the wheel’s speed, it follows that the speed of the wheel (still with respect to the outside) is 10 mph.

Why do I say the belt’s speed would always add to the wheel’s speed? For the same reason that if the wheel were going 0 mph, and the belt 5 mph, then the wheel would thereby be made to go 5 mph. In other words, the belt makes the wheel spin. If the wheel is already spinning, the belt makes it spin faster.

So if the wheel is spinning at 5, and the belt is going at 5, thereby adding 5 to the wheel’s spin, then the wheel is actually spinning at 10, not 5. So the belt (matching the wheel’s speed) is going 10, not 5. But that means the wheel is spinning at 20, not 10. And so on. There is no single determinate speed at which the wheel is turning, and so it turns out the situation as described is an impossible one.

Anyway, point is, all speeds are with respect to the outside.

-FrL-

Relativity is not really a factor at airplane-takeoff velocities. I think this whole scenario is safely Newtonian.

Principle, not theory.

Not quite. If we observe the point of contact between the wheel and the treadmill to be moving at 5 mph relative to us, and an arbitrary point on the treadmill is moving relative to us at 5 mph in the other direction, then the point where the wheel contacts the treadmill is moving away from that same arbitrary “tracking point” at 10 mph.

Think about. You hold onto a matchbox car and place it on a conveyor belt. You put a plastic soldier next to it. You turn the conveyor belt on at 5 mph. At what speed is the point where the matchbox car’s free moving wheel touches the belt moving away from us? Zero. It isn’t moving; we’re holding on to the car. How fast is the car moving away from the soldier? 5 mph, the speed of the belt.

So with the plane, belt moves at 0 mph relative to us, plane moves at 0 mph relative to surface of belt, plane moves at 0 mph relative to us, wheel spins at 0 mph. Speed up plane to 3 mph relative to belt, speed up belt to match. Plane moves at 3 mph relative to surface of belt, 0 mph relative to us, belt moves at 3 mph relative to us, wheel spins at 3 mph. Now increase engines but keep belt constant. Plane moves at 4 mph relative to belt, 1 mph relative to us, belt moves at 3 mph relative to us, wheels spin at 4 mph.

This assumes that moving the belt automatically causes the wheels to spin while the plane remains stationary. I don’t think this is the case. I have a matchbox car and a piece of paper in my kitchen. When I go in and pull the paper back gradually, the matchbox car moves with it. Why would an airplane resting on its landing gear on a runway behave any differently?

If I pull the paper really quickly, it pulls out from under the car, the wheels spin, etc., and it doesn’t move much. But it moves a little. And if the paper were really long, it would eventually move backwards, and eventually reach the speed of the paper.

Throw in some frictionless wheels and whatnot, and sure, the plane stays still no matter how much you speed up the belt, and add a little thrust, and you’ve created a situation where the belt can never match the plane’s speed. But in that case, the belt and the plane have no interaction whatsoever, so why even have the belt in the first place?

Once you decide that belt increase does not mean automatic, persistent increase in wheel speed, the belt’s backwards motion relative to the outside world eventually translate into the plane moving backwards realtive to the outside world. Add a little thrust, and the plane moves forward on the belt, overcoming the belt’s backward motion. At a little more thrust, and the speed of the plane relative to the belt increases, so we increase the speed of the belt accordingly.

Relativity is a factor at any velocity where different frames of references are concerned.

zut’s my new hero. Page after page you calmly explain that their are two equally valid interpretations, that thought experiments aren’t meant to explain the real world, etc. without ever raising your voice or getting snarky. Well done.

My brother posed the question to me of the airplane and the treadmill a few days before it broke on the SDMB. I was reluctant to post in that thread because it turned into such a mish-mash of different arguments, including what the original question meant. Almost universally accepted, however, was the idea that rolling resistance was negligible or non-existant. Hence the argument, however brilliant, that an accelerating treadmill could hold the plane against the thrust of its engines by the torque of its accelerating wheels. It could, of course, but it’s not necessary to invoke this method.

Rolling resistance is not negligible. The force needed to roll a 747 is on the order of 25+ tons. That’s not the force needed to overcome inertia, that’s the force needed to keep it moving at a steady rate along the pavement. Thus the throttle setting for this aircraft rolling down the taxiway is at about 25% of full thhrottle.

We can then set up this steady-state situation: the 747 is sitting on a non-accelerating treadmill rolling at 40 mph with its engines putting out 25% full throttle. It’s not moving simply because the force of roling resistance balances the force of thrust from the engines.

I don’t claim to have any numbers but I would wager that air resistance is a much bigger factor than rolling resistance for a plane taxing. I would wager that you would need a much smaller thrust to keep a plane stationary on a treadmill moving at 40 mph.

Note to moderators. I obviously cannot continue to debate when my position is misrepresented thus. I therefore withdraw myself from this thread, with this note only, that “treis’s” original remark, “There is no part of any force that results in translation and there is no part that results in rotation. 100% of the force is responsible for translation and 100% of the force is responsible for rotation. Linear and angular acceleration are completely independent of each other,” continues to be nonsense.

Cop out to the extreme. You have thus far ignored every argument I have made and refused to even answer the most basic question about your position. You appear to be ignoring the fact that force can easily be multiplied as much as one desires through pullies and levers. Answer my question about the 3 cases I asked earlier and quit being a drama queen.

And I’d take that wager. :wink:

Airport tractors for the heavies are rated at 50,000 lbs. DBP (draw bar pull) and up. Total thrust for a 747 is around 200,000 lbs. Hence, 25% of 200,000 lbs. is 50,000 lbs. You can approximate rolling resistance with a rolling resistance coefficient, RR. It varies from 6 to 10 percent of gross weight. You can Google those terms. Since a fully tanked 747 goes around 700,000 lbs. with an RR of, say, 7% you get a resistance of around 49,000 lbs.

And coming up: rolling resistance actually increases with speed… (Really)

The problem of a wheel on a conveyer belt isn’t so difficult that it should take up all of this time. I went back to my old, old, physics text to review on rotary motion. Having done that I reproduced the development of the relationship between torque and angular acceleration. The development, of course, makes use of F = ma, some kinematic relationships between linear and angular acceleration and the definition of torque as a force at a distance from a center with the force being always at right angles to the line between the center and the point of application of the force.

The result is in this one page paper.

Having satisfied myself, if no one else, that a torque produces only rotation, I’ll apply that to a wheel on a conveyer belt in a later post.

Ha, you should have held out for a monetary wager. You could have made some money off of me. :wink: