There are a couple of opposing factors at play here:
- the amount of mechanical energy pissed away per mile of vehicle travel. This is the rolling resistance of the tires and the aerodynamic drag of the whole vehicle, with the latter being most of it. Aero drag scales with the square of vehicle speed: a car traveling at 80 MPH has about four times the aero drag of a car traveling at 40 MPH, and so will require about four times as much energy per mile.
You may however have noticed that your fuel economy at 40 MPH isn’t four times as good as it is at 80 MPH. And that’s because…
- An engine is less efficient at light load (this is particularly true of gasoline engines, which have higher peak combustion temperatures than diesels (and so lose more of their combustion energy to the cylinder walls through heat transfer before it can be converted to mechanical energy) and also have to suck air past a mostly-closed throttle plate (which takes a surprising amount of effort). This is why automatic transmission quickly shift up and up and up to the highest gear the engine will tolerate: to get RPMs down and (more importantly) to get load up.
So at 80 MPH your engine is operating with decent efficiency (cuz there’s substantial load on it), but you need to burn a lot of gas per mile to make up for the high aero drag losses. At the opposite extreme (10 MPH), there’s very little drag to contend with, but most of the engine’s fuel consumption goes toward simply keeping itself running, and you will get really crappy MPG. The middle ground, typically somewhere between 35 and 55 MPH, is where those two factors cross over and the typical passenger car finds its best fuel economy.
This is an odd assumption, given the wide variety of passenger car configurations (and especially since the MPG figures for such vehicles are public information). It ought to be quickly obvious that a Honda Fit and a Cadillac Escalade, with their very different aerodynamic properties and engine displacements, are going to give very different results.
I don’t have numbers handy, but my suspicion is that an induction motor paired with a VFD has good efficiency at all but the very lightest of loads, which would mean that the best vehicle range comes at a much lower speed (where aero drag is lower) than for a dinosaur-powered car.
An interesting aside:
some time ago in one of XKCD’s “what if” scenarios, Munroe pointed out that miles per gallon, if inverted to become gallons per mile, basically represents units of volume divided by length - which is simply area. In effect, gallons per mile represents the cross-sectional area of a stream of gasoline used by you car as it moves down the road. Example:
30 miles per gallon = 0.033333333 gallons of fuel per mile traveled
0.0333333333 gallons per mile = 0.004456019 cubic feet of fuel per mile traveled
0.004456019 cubic feet per mile = 8.43943E-07 cubic feet of fuel per foot traveled
8.43943E-07 cubic feet of fuel per foot traveled = 8.43943E-07 square feet
8.43943E-07 square feet = 0.000122 square inches
That’s a circle 0.0124 inches in diameter. So if your car gets 30 MPG, you can imagine a stream of gasoline 0.0125 inches in diameter stretching the length of your trip, and that’s how much your car will use during that trip.