http://www.madblast.com/view.cfm?type=FunFlash&display=1781
It’s a mindreader game. It worked 10 times in a row for me. I can’t figure out how it works though. Any idea?
The mathemtaical instructions they give you will always yield a result that’s divisible by 9, from 08 to 81. If you look at the page where they show the symbols, you’ll note that all multiples of 9 from 09-81 have the same symbol, and that’s the symbol it shows on the last screen.
The formula they give you to use always leaves you with 9 or a multiple of 9. On the second page, these all always have the same symbol for any one play.
In other words, the symbol used for 9 and all its multiples may vary from play to play, but for any one play, they all have the same symbol.
That makes it a tad easier to guess.
Ugly
Er, make that 09 to 81. So the possible results are 09, 18, 27, 36, 45, 54, 63, 72, and 81
Just for the heck of it, I’ll throw in the logic that guarantees a result that is divisible by nine:
Take any two digit number represented by AB where A is the “tens” digit and B is the “ones” digit.
The total value of your number is 10**A* + B
Subtract A and the result is 9A* + B
Subtract B and the result is 9A*, always a number divisible by 9. In fact, if you follow the steps, your result is always nine times your initial “tens” digit. Your “ones” digit is irrelevant.
Dang, you cats are smart.
I’d dearly love to know how “Card Trick” from this site www.beechbrook.com/pte/ works. Relax, folks! It’s not a commercial site. Every time I’ve tried the thing, it’s “guessed” correctly. How?!?
It’s very easy.
None of the cards in the first selection are included in the second. Therefore, whatever card you pick from the first selection will never be present in the second, and the trick works every time. They maintain the illusion by having similar cards in both, but they’re not equal.
Someone tried explaining me that before…but I’m still confused by it…
Okay, I don’t want to run it myself, but I’ve seen the trick before, and here’s how it works. The first time through, they might give you these five cards:
8H 9S 7D 7C 8C
and then they remove your card and give you this:
9C 7S 8D 8S
As you can see, none of the cards the second time through were there the first time, and so no matter which one you picked, it will be missing. Since they use cards that look more or less the same, you don’t notice whether a card is missing unless you concentrate on it.
Yea, I played it twice, the second time concentrating about the cards. Got it!
If you want a handy simple card trick you can “load” a deck with a repeating pattern, like this:
KH 10D 2C 3S 6H 8D 9D KD 10H 2S 3C 6S 8C 9S KS 10S 2D 3D 6C 8H 9C KC 10C 2H 3H 6D 8S 9H
Put simply, you arrange 28 cards with a repeating pattern K-10-2-3-6-8-9 (or any other 7 cards). You let your sucker cut the deck and then give him seven cards. No matter where the cut happens, the seven cards will always consist of K-10-2-3-6-8-9. You can then amaze the sucker by naming the ranks of the cards drawn. You can make this more elaborate by cannibalizing 7 decks so you get the exact same pattern of 7 cards (7 times, to make up a seemingly normal-sized “deck” of 49 cards) and you’ll be able to predict the ranks AND the suits of the drawn cards.
Later on after you practice a lot, you can even let the sucker shuffle a deck, provided you use a bit of misdirection to swap in your “loaded” deck, let him cut (even multiple times), then proceed as above.