I forgot to ask my mathematics teacher for help on this problem and I can’t figure it out:
Here’s the link (you are supposed to find x**:
http://acr.kendallhunt.com/KeyPressPortalV5.0/ImportingCourses2/DG/images/589_img_9.gif
Oh never mind. I know how to do it now!
Glad we could help.
I get x = 6.
I can’t see the theta’s, in the image.
You know the saying. In order to solve any problem you need two people, one of whom need know nothing about it. 
It’s easy to do with trig, but that’s probably cheating.
The more geometric way:
Call the points of the large triangle A, B, and C going clockwise from the top. Call the point to the left of line segment x point D, and the one to the right E.
First, note that angle DEC is the same as the marked angles to to the parallel line rule. Then, triangle DEC is isosceles and line segments DE (also called x) and CD are the same length.
Triangle AED is similar to triangle ABC, so the line segments they’re made from must also be similar. Therefore, 15/(AD) = 10/x, or 15x = 10(AD). We also have (AD) + x = 15, or (AD) = 15 - x.
Substituting, we have 15x = 10(15 - x), or 15x = 150 - 10x, or 25x = 150, or x = 6. QED, or something.
I found it! There it is!
The son of the squaw on the hippopotamus is equal to…
Aw, never mind.
