I heard Neil DeGrasse Tyson say something like this: “If you take a globe and imagine the ISS orbiting around the globe, it’s height above the globe surface would be 1/16 of an inch.”
He didn’t specify the size of the globe. Now, my addled brain couldn’t get the math to work to see if this is true. My assumptions: the ISS is 230 miles above the surface of the earth. The earth’s radius is 4000 miles (approx.).
So, is this true? How big would the globe have to be to make this true? And what is the math (simplified!) to show this is true?
The radius of Earth is 3959 miles, and your run of the mill 12" globe has a radius of 6 inches. The radius of the ISS orbit is 4189 miles, so on that 12" globe it would be ~0.35 inches off the surface.
Geostationary orbit is 22,236 miles above the surface. We were using 4189 for the ISS orbital height, so geostationary would be 5.3 times that, or almost exactly 2 inches!
The white dot at the upper right corner represents an object at about 600km from the surface of the earth. The ISS is even closer than that at 300-400 km