Intensity, the Photoelectric Effect & Light-as-a-Particle

Thinking out loud here, I’ve been very confused for at least the past hour. I think my ultimate question is what’s in bold at the bottom.

Very simple ( :wink: ) request - can someone explain how the photoelectric effect leads away from seeing light as a wave and towards seeing light as a particle?

I’ve been going through all the Google and Wikipedia entries on the subject, and none of them are really clear enough.

Here is a quote about the experiment of one Phil Lenard:

Maybe my confusion here is about the relationship between energy, intensity and frequency in light.

Now increasing the intensity of the light means increasing the amount of energy that it transmits, yes? So why doesn’t that increase the energy of the emitted electrons? Or does intensity just mean you change the amount of light being emitted? In which case, why would the amount of light being emitted cause the electrons to be emitted more energetically? Wouldn’t you just expect there to be more of them, as per the results of the experiment?

The part you’re missing is that the systems are quantized – there is a certain energy required to kick and electron out. Below that energy, no electronss get kicked up to the conduction band, regardless of how intense the light is. (multiphoton effects are negligible until you get to monumental intensities, like what you get from a high-power laser). The photoelectric effect is one of many effects that suggest that energy is quantized. If the light energy is carried in the form of a particle, it’s easy to see how it’s quantized – so much energy per photon. Increasing intensity means increasing the number of these photons. And if one photon per electron is needed to induce the photoelectric effect, it all fits together, because if the energy per photon is insufficient, then changing the number of them you throw at the metal still won’t increase the number of libearted electrons.

If light is a wave, on the other hand, then , regardless of the energy, I can eventually get the energy delivered by the wave up to that needed to liberate an electron by simply dialing the intensity up.

A further ‘amplification’, if you will. If light is strictly a wave, then increasing the intensity increases the amplitude of the wave. The amplitude is the maximum strength of the electromagnetic field of the wave. So, you’d expect a stronger field to accelerate the electrons more, thus causing them to be ejected with higher energy. Also, you’d expect that you could still eject electrons with “red” (lower energy) light, if the intensity were high enough.

But, as it turns out, while the field strength does increase with increasing intensity, it does that by having more photons. Thus, more emitted electrons, but all at the same energy as before. And low energy (low frequency) light can’t eject an electron, no matter how intense, because the energy is absorbed one photon at a time.

Does that make sense?

-Rick

Or another way to put it: If I have a single photon, with almost enough energy to liberate an electron, then it’ll almost liberate an electron. If I instead have two photons with that energy, they still won’t liberate an electron; instead, they’ll almost liberate two different electrons.

A very nice layman’s explanation can be found here.

http://www.colorado.edu/physics/2000/quantumzone/photoelectric.html

My understanding was that the problem with the photoelectric effect and wave light is that the photoelectricity starts to flow as soon as the light hits the target, and does not wait until enough uniformly distributed energy would have hit the region occupied by an electron. Therefore the energy must arrive in packages.