Different projections serve different aims. Mercator was more for navigation, the polar latitudes are obviously distorted. (In your typical schoolroom map, Canada looks a helluva lot bigger than the USA - it’s not reall that much bigger). There are conic projections for better depiction of near-polar regions, there’s the orange-peel map for more accurate depiction of surface area without distortion, etc. Depends on your aim.
If all you want is to display county data, and only for the continental USA, a sort of cylindrical projection is probably sufficiently undistorted.
A degree of Longitude at 49 degrees lat. is 45.5 miles; at 25 degrees lat (bottom of Florida) a degree of longitude is 62.73 miles. A degree of lat is pretty much the same in both cases, about 69 miles. The average for longitude in this range is about 54 miles.
If you just translate lat/long to x, y and use the intermediate value for longitude ( each lat degree translates into 61 pixels, each degree of long translates into 54 pixels, scaled appropriately. You map will be slightly stretched at the top and slightly squashed at the bottom, but not more than a typical Mercator projection.
So let’s say the map for is for 65W to 125W long (60 degrees), 25N to 50 N (25 degrees) (round numbers, sorry, clips off the Florida Keys. Lower right is 0,0. lets say this is 1000 pixels high, so 1 degree lat is 1000/25=40 pixels vertical.
By the same scale, if 40 pixels is 61 miles, 54 miles would be 35.41 pixels.
(Note 25º x 61 miles is 1525 miles). A rectangle 1 degree each side would look like on the map scale 61 miles high and 54 miles wide, so 40 pixels high and about 35.4 pixels wide in the map image.
your map would be 60º x 35.4 = 2,144 pixels wide.
A point A(aº b’ c") , D (dº e’ f") lat and long would be - translate to decimal - A = a + b/60 + c/3600 and B = (d+e/60+f/3600)
Translate these to pixel coordinates x,y - lower right is 0,0 pixels, 25º lat 65º long (and x is vertical, y is horizontal)
x= (A-25)*40
y=(B-65)*35.4
So the top left corner of the map is x=(50-25)*40 =1000, y=(125-65)*35.4 = 2124pixels somewhere in the middle of Vancouver Island.
Assuming I can still do math.
if you want the pixels to number left to right, I leave this as an exercise for the reader.
If you have a different goal in a map - undistorted area, or true distances - well that doesn’t work well for significant chunks of a spherical surface. All maps are a compromise.